Answer:
21,600
Step-by-step explanation:
Answer: (0, -6)
Explanation:
6x - 6 = -4x - 6
10x = 0
x = 0
y = 6(0) - 6
y = 0 - 6
y = -6
25+30x=65+20x
-20x -25
------ ------
10x=40
10 10
x=4
I crossed multiplied but in a weird way because of how this is. Anyways, I hoped I helped you. :D
Answer:
Area of square pyramid is
.
Step-by-step explanation:
Diagram of the given scenario is shown below,
Given that,
The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is
. The side of the square is
and The height of each triangle is
.
So, Area of Square shape = ![154 \ m^{2}](https://tex.z-dn.net/?f=154%20%5C%20m%5E%7B2%7D)
Side of square = ![230 \ m](https://tex.z-dn.net/?f=230%20%5C%20m)
Height of each triangle = ![187 \ m](https://tex.z-dn.net/?f=187%20%5C%20m)
Finding the Height of triangular shape which is here known as slant height.
In Δ ABO, applying Right angle pythagorean Theorem,
Base
= ![\frac{230}{2} = 115\ m](https://tex.z-dn.net/?f=%5Cfrac%7B230%7D%7B2%7D%20%3D%20115%5C%20m)
Height
= ![187\ m](https://tex.z-dn.net/?f=187%5C%20m)
Now,
∴ ![AB^{2} = AO^{2} \ + \ BO^{2}](https://tex.z-dn.net/?f=AB%5E%7B2%7D%20%3D%20AO%5E%7B2%7D%20%5C%20%2B%20%5C%20BO%5E%7B2%7D)
⇒ ![AB= \sqrt{AO^{2} \ + \ BO^{2} }](https://tex.z-dn.net/?f=AB%3D%20%5Csqrt%7BAO%5E%7B2%7D%20%5C%20%2B%20%5C%20BO%5E%7B2%7D%20%20%7D)
⇒ ![AB= \sqrt{187^{2} \ + \ 115^{2} }](https://tex.z-dn.net/?f=AB%3D%20%5Csqrt%7B187%5E%7B2%7D%20%5C%20%2B%20%5C%20115%5E%7B2%7D%20%20%7D)
⇒ ![AB= \sqrt{34969 \ + \ 13225 }](https://tex.z-dn.net/?f=AB%3D%20%5Csqrt%7B34969%20%5C%20%2B%20%5C%2013225%20%20%20%7D)
⇒ ![AB= 219.53 \ m](https://tex.z-dn.net/?f=AB%3D%20219.53%20%5C%20m)
Then,
Area of square pyramid = ![area \ of \ square + \ 4\times area \ of \ traiangle](https://tex.z-dn.net/?f=area%20%5C%20of%20%5C%20square%20%2B%20%5C%204%5Ctimes%20area%20%5C%20of%20%5C%20traiangle)
=
= ![230\times 230 \ + 2\times 219.53\times 230](https://tex.z-dn.net/?f=230%5Ctimes%20230%20%5C%20%20%2B%202%5Ctimes%20219.53%5Ctimes%20230)
= ![52900 + 100983.8](https://tex.z-dn.net/?f=52900%20%2B%20100983.8)
= ![153883.8 \ m^{2}](https://tex.z-dn.net/?f=153883.8%20%5C%20m%5E%7B2%7D)
Hence, Area of square pyramid is
.