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3 years ago

If f(x)=4x^2-3 and g9x)=x+1, find (f-g)(x)

Mathematics

1 answer:

kiruha [24]3 years ago

5 0

Step-by-step explanation:

(f-g)(x) = f(x) - g(x)

the same applies to all other basic operations (like addition, multiplication, ...).

so,

(f-g)(x) = 4x² - 3 - (x + 1) = 4x² - 3 - x - 1 = 4x² - x - 4

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Why is (x-3) NOT a factor of x3+2x2-5x-6

ivolga24 [154]

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Step-by-step explanation:

Given expression is:

$x^3+2x^2-5x-6$

We have to check if x-3 is a factor of given expression

In order for x-3 to be a factor of expression, we have to put x-3 = 0 => x=3 in expression.

If the expression is zero at x=3 then x-3 is a factor of expression otherwise not.

So putting x=333 in expression

$=(3)^3+2(3)^2-5(3)-6\\= 27+2(9) - 15-6\\= 27+18-15-6\\= 45-21\\=24 \neq 0$

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Keywords: Polynomials, expressions

Learn more about polynomials at:

#LearnwithBrainly

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=z%5E%7B7%7D%3D128i" id="TexFormula1" title="z^{7}=128i" alt="z^{7}=128i" align="absmiddle" cla

abruzzese [7]

If z ⁷ = 128i, then there are 7 complex numbers z that satisfy this equation.

$z^7 = 128i = 2^7i = 2^7e^{i\frac\pi2}$

$\implies z=\sqrt[7]{2^7} e^{i\frac17\left(\frac\pi2+2n\pi\right)}$

(where n = 0, 1, 2, …, 6)

$\implies z = 2 e^{i\left(\frac\pi{14}+\frac{2n\pi}7\right)}$

$\displaystyle\implies z = 2 \left(\cos\left(\frac\pi{14}+\frac{2n\pi}7\right)+i\sin\left(\frac\pi{14}+\frac{2n\pi}7\right)\right)$

3 0

3 years ago

Here are the scores of 16 students on an algebra test. 63, 64, 68, 71, 72, 73, 74, 75, 75, 85, 86, 87, 90, 91, 92, 93 Notice tha

Studentka2010 [4]

here you go, I think this is right

3 0

3 years ago

If p − 1 is a factor of p4 + p2 + p − k, the value of k is

amid [387]

Hello,

--------4----3----2----1----0
.........1.....0.....1.....1.....-k
p=1..........1.....1.....2 ....3
.........1.....1.....2.....3.....0

==>-k+3=0==>k=3

6 0

3 years ago

Read 2 more answers

IQ scores are measured with a test designed so that the mean is 116 and the standard deviation is 16. Consider the group of IQ s

butalik [34]

Answer:

So the z-scores that separate the unusual IQ scores from those that are usual are Z = -2 and Z = 2.

The IQ scores that separate the unusual IQ scores from those that are usual are 84 and 148.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 116, \sigma = 16$