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2 years ago

Need some help with this question in the image

Mathematics

2 answers:

Andrew [12]2 years ago

6 0

Answer:

a. - 77

b. 4

c. 5x-14

d. 14

Step-by-step explanation:

a. 2-(7*9)-16

=> 2-63-16

=>(-61) - 16

=> -77

b.64 / 4+(3*4)

=> 64 / 4+12

=> 64 / 16

=> 4

c. 3x+2(x-7)

=> 3x+2x - 14

=> 5x-14

d. 5 + 6^2/ 4

=> 5+ 36/4

=> 5+9

=> 14

Leya [2.2K]2 years ago

3 0

Answer:

1a. first 7×9=63 Then substracting 16 we get 47 and 2-47= -45

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Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

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Need some help with this question in the image ​

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