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Lyrx [107]
2 years ago
15

Please solve for X and Y

Mathematics
1 answer:
Tema [17]2 years ago
7 0

CCan you make it visible to see, please!CCan

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Need help with 1 & 2 anyone wanna help I will mark you brainliest
xz_007 [3.2K]
1. First step: To get a term of x by itself, add 5 to both sides

Second step: This will become 3x<24

Third step: To separate 3x, divide everything by 3: 3x÷3 < 24÷3

Step four: x < 8

2. First subtract both sides by 12: - 2x + 12 - 12 < - 4 - 12

Second: This becomes - 2x < -16

Third: Divide by -2 to get x by itself - 2x ÷ - 2 > -16 ÷ - 2 Note: If you divide by a negative number, the inequality sign switches. This is a really important step that most students forget.

Fourth: x>8

Note: Try plugging in values when you are done if you are uncertain you have the right answer.
6 0
3 years ago
BRAINLIEST AND EXTRA 50 POINTS
pychu [463]

Answer:

16/13

Step-by-step explanation:

Multiple inverse for 13/16 is 16/13

4 0
3 years ago
Read 2 more answers
A cylinder-shaped drainage pipe 66 in. long measures 25.12 in. around.
Darina [25.2K]
V=hpir^2

tricky, they didn't give us radius
they just gave circiufmerece

c=2pir
25.12=2pir
divide by 2 both sides
12.56=pir
divide by 3.14 both sides
4=r

subsitutet

v=hpir^2
v=66pi4^2
v=66pi16
v=1056pi
v=3315.84 cubic inches

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=4x%5E%7B0%7D%20x16x%5E%7B0%7D" id="TexFormula1" title="4x^{0} x16x^{0}" alt="4x^{0} x16x^{0}"
statuscvo [17]

Answer:

64

Step-by-step explanation:

its just how it is

8 0
3 years ago
Make r the subject of the formula <br><img src="https://tex.z-dn.net/?f=v%20%3D%20%5Cpi%20%5C%3A%20h%20%7B%7D%5E%7B2%7D%28r%20-%
Vaselesa [24]

Answer:

\boxed{r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} } }

Step-by-step explanation:

Solve \:  for \:  r:  \\  =  >   v= \pi {h}^{2}(r -  \frac{h}{3}  ) \\  \\  v=\pi {h}^{2}(r -  \frac{h}{3}  )is \:  equivalent  \: to   \:   {h}^{2}\pi(r -  \frac{h}{3}  ) = v: \\  =  >  {h}^{2}\pi(r -  \frac{h}{3}  ) = v \\  \\ Divide  \: both \:  sides  \: by  \: \pi  {h}^{2} :  \\  =  > r -  \frac{h}{3}  =  \frac{v}{\pi {h}^{2} }  \\  \\ Add \:   \frac{h}{3}  \:  to  \: both \:  sides:  \\  =  > r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} }

8 0
3 years ago
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