All categories

2 years ago

Whoever gets it right can have brainliest, but answer ASAP!

Mathematics

2 answers:

sdas [7]2 years ago

6 0

Answer:

6.52

Step-by-step explanation:

6.52

lisov135 [29]2 years ago

3 0

Answer is: 6.52
Hope this helps

You might be interested in

Find and simplify the difference quotient of the form, <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh

Anastasy [175]

With $f(x)=-10x+9$ , we have

$f(x+h) = -10(x+h) + 9 = -10x + 9 - 10h$

Then the difference quotient is

$\dfrac{f(x+h)-f(x)}h = \dfrac{(-10x+9-10h)-(-10x+9)}h = \dfrac{-10h}h = -10$

since h ≠ 0.

7 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

Yuri [45]

Let the curve C be the intersection of the cylinder

$16x^2+y^2=16$

and the plane

$x+y+z=1$

The projection of C on to the x-y plane is the ellipse

$16x^2+y^2=16$

To see clearly that this is an ellipse, le us divide through by 16, to get

$\frac{x^2}{1}+ \frac{y^2}{16}=1$

$\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1$ ,

We can write the following parametric equations,

$x=cos(t), y=4sin(t)$

for

$0\le t \le 2\pi$

Since C lies on the plane,

$x+y+z=1$

it must satisfy its equation.

Let us make z the subject first,

$z=1-x-y$

This implies that,

$z=1-sin(t)-4cos(t)$

We can now write the vector equation of C, to obtain,

$r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))$

The length of the curve of the intersection of the cylinder and the plane is now given by,

$\int\limits^{2\pi}_0 {|r'(t)|} \, dt$

But

$r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))$

$|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}$

$\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184$

Therefore the length of the curve of the intersection intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0

3 years ago

I need steps and help please

stich3 [128]

Solve 4x=3x+10
And then that what your answer should be

4 0

3 years ago

If a rotation takes triangle CAT to C'A'T', what is C'T'?

xxMikexx [17]

I think it is negative 1 I’m not sure tho

7 0

3 years ago

The resultant of two forces acting on a body has a magnitude of 80 pounds. The angles between the resultant and the forces are 2

kifflom [539]

The basic idea is that you form a parallelogram with those two vectors as the two different side lengths another way to see it: start at the tip of one vector and move in the same direction as the other vector (and the same length as the other vector)

With any parallelogram, the adjacent angles are supplementary

180-52-20= 108 degrees

5 0

3 years ago