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Bumek [7]
3 years ago
15

The price of a pair of shoes was first increased by 10% and then decreased by 10%. the final price was what percent of the origi

nal price
Mathematics
1 answer:
Valentin [98]3 years ago
8 0
I think the answer you are looking for is 99%.

100 + 10% = 110. 110 - 10% = 99. that’s how i got 99.
You might be interested in
Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right
juin [17]

Answer:

RT = 12 units

Step-by-step explanation:

From the figure attached,

ΔSRQ is right triangle.

m∠R = 90°

An altitude has been constructed from point T to side SQ.

m∠RTQ = 90°

By applying geometric mean theorem in triangle SRQ,

\frac{\text{RT}}{\text{ST}}=\frac{\text{TQ}}{\text{RT}}

\frac{x}{9}=\frac{16}{x}

x² = 16 × 9

x² = 144

x = √144

x = 12

Therefore, length of altitude RT is 12 units.

5 0
3 years ago
Find the value of x<br>​
riadik2000 [5.3K]

Answer:

need more information

Step-by-step explanation:

more information is needed to answer this question

3 0
2 years ago
Can someone please help me with this question??
posledela

Answer:

In order of least money saved to most money saved: Katrina, Susan, Gabrielle, Savanna

Step-by-step explanation:

You can first change all of them to either percentages or fractions with the same denominator. I chose to use percentages. Thus Savanna's percentage of money saved would be 90%, Katrina would've saved 80% and Susan would've saved around 83%.

From here you just order from least to greatest.

3 0
2 years ago
Read 2 more answers
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
Given the equation (x+a)^2(x-2)=x^3+bx^2+12x-72 find a and b
GaryK [48]
Isolate the variable by dividing each side by factors that don't contain the variable.

a=-  \frac{ x^{2}-  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,-  \frac{ x^{2}+  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

Solve for b by simplifying both sides of the equation then isolating the variabel.

b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

Hopefully i helped ^.^ Mark brainly if possible 
 

7 0
3 years ago
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