All categories

2 years ago

A snack bar weighs 61g, and 10% of the weight is apple. How many

Mathematics

2 answers:

eduard2 years ago

8 0

Answer:

61×10/100

=610/100

=6.1 g

quester [9]2 years ago

5 0

Answer:

6.1g

Step-by-step explanation:

Snack bar: 61g

Apple: 10% of 61g

10/100 = 0.1

0.1 * 61 = 6.1g

There are 6.1g of apple in the snack bar.

Hope this helps!

You might be interested in

Please help really confused

marysya [2.9K]

X intercept: (- 1/7, 0)
Y intercept: (0, 1/4)

3 0

3 years ago

i need help and answers asapppppppppppppp. I WILL MARK BRAINLIEST AN THANKS TO EVERY ONE (i wont mark brainliest if the whole qe

Sonja [21]

Hope this can help you :)

5 0

3 years ago

Critique Reasoning James says is greater than 10. Is James correct? Explain.

Dafna1 [17]

The is answe is less than because I have to get them up

3 0

2 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago

The function y = x2 is transformed to y = (x + 4)2. Which statement is true about the transformed function? It is an even functi

xxMikexx [17]

Even function: f(-x) = f(x). If you replace x by -x you should find the same function.
Odd function: f(-x) = -f(x). If you replace x by -x you find the same function with opposite sign;
Is f(-x) = f(x)?
f(x) = (x+4)² = x² + 8x +16
f(-x) = (-x+4)² = x² - 8x + 16, then it's not an even function

Is f(-x) = -f(x)?
f(-x) = (-x+4)² = x² + 8x + 16 , then it's not an odd function
It is neither an even nor an odd function

7 0

3 years ago