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xz_007 [3.2K]
2 years ago
9

A prize is divided in the ratio 5:1 if the larger share is £65 what is the total prize?

Mathematics
2 answers:
xxTIMURxx [149]2 years ago
7 0

Answer:

<u>£78</u>

Step-by-step explanation:

Let the total value be T.

  • £65/T = 5/(5 + 1)
  • £65/T = 5/6
  • T = 65 x 6 / 5
  • T = 13 x 6
  • T = <u>£78</u>
Paha777 [63]2 years ago
6 0

Answer:

£78

Step-by-step explanation:

65 divided by 5= £13

13+65=£78

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A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su
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Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let \mu_1 = mean sales per market in Region 1.

\mu_2  = mean sales per market in Region 2.

So, Null Hypothesis, H_0 : \mu_1-\mu_2 = 0      {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, H_A : > \mu_1-\mu_2\neq 0      {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is <u>Two-sample t-test statistics</u> because we don't know about population standard deviations;

                            T.S.  =  \frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }   ~  t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean sales in Region 1 = 84

\bar X_2 = sample mean sales in Region 2 = 78.3

s_1  = sample standard deviation of sales in Region 1 = 6.6

s_2  = sample standard deviation of sales in Region 2 = 8.5

n_1 = sample of supermarkets from Region 1 = 12

n_2 = sample of supermarkets from Region 2 = 17

Also, s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times  s_2^{2}  }{n_1+n_2-2} }  = s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times  8.5^{2}  }{12+17-2} } = 7.782

So, <u><em>the test statistics</em></u> =  \frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }  ~   t_2_7

                                   =  1.943  

The value of t-test statistics is 1.943.

 

Now, at a 0.02 level of significance, the t table  gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have<u><em> insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

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The linear regression equation is y = 61. 93x - 1. 79. According to the model, the slope can be interpreted as:
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The slope of the linear regression equation y = 61. 93x - 1. 79 is attached with the response.

<h3>What is linear regression?</h3>

Linear regression is the most primary and generally used predictive research. Regression calculations are utilised to represent data and to describe the association.

The slope of the linear regression equation represented in the graph is the straight-line cutting the intercepts on the y axis at 1.79.

To know more about linear regression follow

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The percentile of 1.2 equals?
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It’s 0.3 because that’s the answer

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