Question

A 23.6 g sample of NagPO4 (molar mass 163.94 g/mol) is dissolved in enough water to produce

Answer 1

Taking into account the definition of molarity,  the concentration of Na₃PO₄ in solution is 0.192$\frac{moles}{lliter}$.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{lliter}$.

Concentration of Na₃PO₄ in solution

Being the molar mass of Na₃PO₄ 163.94 g/mole, that is, the amount of mass that a substance contains in one mole, the amount of moles that contains 23.6 g sample of Na₃PO₄ is calculated as:

$23.6 gramsx\frac{1 mole}{163.94 grams} = 0.144 moles$

Then you know:

• number of moles= 0.144 moles
• volume= 750 mL= 0.750 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

$Molarity=\frac{0.144 moles}{0.750 L}$

Solving:

Molarity= 0.192$\frac{moles}{lliter}$

Finally, the concentration of Na₃PO₄ in solution is 0.192$\frac{moles}{lliter}$.

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