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zzz [600]
2 years ago
6

A 23.6 g sample of NagPO4 (molar mass 163.94 g/mol) is dissolved in enough water to produce

Chemistry
1 answer:
Gnom [1K]2 years ago
8 0

Taking into account the definition of molarity,  the concentration of Na₃PO₄ in solution is 0.192\frac{moles}{lliter}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{lliter}.

<h3>Concentration of Na₃PO₄ in solution</h3>

Being the molar mass of Na₃PO₄ 163.94 g/mole, that is, the amount of mass that a substance contains in one mole, the amount of moles that contains 23.6 g sample of Na₃PO₄ is calculated as:

23.6 gramsx\frac{1 mole}{163.94 grams} = 0.144 moles

Then you know:

  • number of moles= 0.144 moles
  • volume= 750 mL= 0.750 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

Molarity=\frac{0.144 moles}{0.750 L}

Solving:

Molarity= 0.192\frac{moles}{lliter}

Finally, the concentration of Na₃PO₄ in solution is 0.192\frac{moles}{lliter}.

Learn more about

molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

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