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marysya [2.9K]
3 years ago
14

The temperature of a gas rose from 250K to 350K. At 350K, the volume of the gas was 3.0L. If the pressure did not change, what w

as the initial volume of the gas?
Please give an explanation and I will give you Brainliest :)
Chemistry
2 answers:
LenaWriter [7]3 years ago
7 0
Hey there,

So. . I believe is how you do it. I did 350 x 3.0 and it got me 1,050.
We always multiply it by when it come to the initial volume of the gas.

Hope this helps.

~Jurgen<span />
Oksi-84 [34.3K]3 years ago
7 0
Do 350,000 x 3.0 = 1,050,000 so you would do 250,000 x 3.0
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(p1)(V1)/(T1) = (p2)(V2)/(T2)
(1.00 atm)(V) / (273 + 25K) = (40.0 atm)(V/10) / (273 + T)
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3 years ago
A nuclear power plant operates at 40.0% efficiency with a continuous production of 1042 MW of usable power in 1.00 year and cons
Sergio039 [100]

Answer:

3.00 x 10^-11 joules / atom of U-235

Explanation:

We know that the formula for Power = Work done (w)/Time (t)

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From the formula P = W/t

W = Power (P) * Time (t)

The SI unit for Time is seconds, hence we change 1 year in seconds

1yr * 365 days/yr * 24hrs/day * 60mins/hr * 60 secs/min = 31536000 secs

It was stated in the question that the plant operates at an efficiency of 40%,

Thus to get the true power we divide the power provided in the question by 0.4 or 40%

= X(0.4) = 1042MW

True Power X = 1042/0.4 = 2605MW

Thus true power = 2605 * 10^6 Watts

Now we have the time in seconds and true power in Watts, we then find the work done.

From our above formula P = W/t

W = P*t = (2605* 10^6) (31536000) =

Finally, we can solve for our energy (work):

P = W / T        PT = W = (2880x10^6) (31536000) = 8.22 x 10^16 joules

We then calculate the amount of energy released by only 1 single uranium-235 atom.

= 8.22 x 10^16 joules / 1.07x10^6 g U-235 (235 g / 1 mol)(1 mol/6.0210^23 atoms)

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5 0
3 years ago
The graph above shows how the price of cell phones varies with the demand quantity. The equilibrium price for cell phones is ___
elena-s [515]

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8 0
3 years ago
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The reaction between carbon tetrachloride, CCl4, and water, H2O, to form carbon dioxide, CO2, and hydrogen chloride, HCl, has a
Ber [7]

Answer:

1) a) It is a slow reaction kinetically.

2) a) It is a catalyst.

3) c) It lowered the activation energy of the reaction.

Explanation:

<em>1) The reaction between carbon tetrachloride, CCl₄, and water, H₂O, to form carbon dioxide, CO₂, and hydrogen chloride, HCl, has a ΔG° value of -232 kJ/mole, and so is thermodynamically favored. But when you mix carbon tetrachloride with water, no change is observed. What is a possible explanation for this? </em>

<em>a) It is a slow reaction kinetically.</em>  TRUE. This is the most likely explanation of why no change is observed.

<em>b) The activation energy of the reaction is too small.</em>  FALSE. Slow reactions have a large activation energy.

<em>c) The reaction is not spontaneous. </em> FALSE. ΔG° < 0 so the reaction is spontaneous.

<em>d)The reaction is not favored thermodynamically.</em> FALSE. ΔG° < 0 so the reaction is favored thermodynamically.

<em>2) What word best describes the role that the palladium plays in the reaction between propene and hydrogen above?</em>

It is a catalyst because it increases the rate of the reaction without being altered by the end of the reaction.

<em>3) What did the palladium do to increase the rate of the reaction between the propene and hydrogen? </em>

<em>a)It changed the thermodynamic equilibrium.</em>  FALSE. Catalysts don't affect equilibrium

<em> b)It made the Gibbs free energy of the reaction more positive.</em>  FALSE. Catalysts don't affect Gibbs free energy.

<em>c)It lowered the activation energy of the reaction.</em>  TRUE. According to the Arrhenius equation, the lower the activation energy, the higher the rate constant, and the higher the rate of reaction. This is how catalysts act.

<em>d)It increased the activation energy of the reaction.</em> FALSE.

7 0
3 years ago
2AlCl3 --&gt; 2Al + 3Al2
Eva8 [605]

Answer:

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Explanation:

2AlCl3 --> 2Al + 3Al2 If you produce 15 moles of Al, how many grams of AlCl3 decomposed? ​

FIRST, you need to write down the the correct reaction.  Your equation makes no sense

here is the correct question

2AlCl3 --> 2Al + 3Cl2    If you produce 15 moles of Al, how many grams of AlCl3 decomposed?

for every mole of Al produced, we decomposed a mole of ​AlCl3

so we produced 15 moles of Al, so we decomposed 15 moles of AlCl3

15 moles are 15 X 106.5 = 1597,5 gm AlCl3 decomposed

7 0
2 years ago
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