Supervisors counting cash receipts daily is an example of:.

Why is real GDP a more accurate measure of an economy's production than nominal GDP?

Verizon [17]

Answer:

The correct answer is option B.

Explanation:

Nominal GDP measures economic growth at current prices. It measures the value of output produced on the basis of current prices. It is thus not an inflation measure of economic growth as it includes the change in the price level.

Real GDP is an inflation-adjusted method to measure economic growth. It measures a change in economic output on the basis of constant. It is thus considered a more accurate measure of the economic growth of a nation as it is not influenced by changes in the price level.

6 0

3 years ago

Each wholesale bag of flour is sold in 25kg bags. Using this information, calculate a new column of data of that works out how m

Sav [38]

Answer:

I know the answer

Explanation:

6 0

3 years ago

Net credit sales for the year are $750,000. The end of year accounts receivable balance is $160,000. The allowance for doubtful

alexandr402 [8]

Answer: $3000

Explanation: Allowance for doubtful accounts is the contra account to accounts receiveable when all the bad debts need to be accounted for. The bad debts reduces the accounts receivable line but all bad debts are actually deducted from the allowance for doubtful accounts.

The allowance for doubtful accounts for that year is calculated as 5% of the accounts receivable balance. This amounts to $8000 (160000 x 5%) before bad debts have been accounted for. Allowance for doubtful accounts moves in the opposite direction as accounts receivable because it is a contra account to this line item. At the end of the year before year end closing entries are done, and after the bad debts have been accounted for, the balance on the allowance for doubtful accounts is $5000.

This means that bad debts for that year is:

8000 (balance before bad debts have been accounted for)

- 5000 (balance after bad debts have been accounted for)

= $3000.

5 0

3 years ago

The circles shown to the right are similar but not exactly the same. this is an example of

kumpel [21]

This is an example of variation. The coefficient of variation, also referred to as the Spearman coefficient of variation, is a statistical measure that informs us about the relative dispersion of a data set. Its calculation is obtained by dividing the standard deviation<span> between the absolute value of the average of the set and it is usually expressed as a percentage for its better understanding.</span>

4 0

3 years ago

An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi

Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

$\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}$

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

$1000000\sqrt{9+x^{2}$

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)$

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000$

$f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}} = 500000\\\frac{2x}{\sqrt{9+x^2}} = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\$

And we plug square root of 3 in the original cost function ad we get

$f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\$

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0

3 years ago