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Eddi Din [679]
3 years ago
9

Simplify cos^4x+2cos^2xsin^2x+sin^4x

Mathematics
1 answer:
KonstantinChe [14]3 years ago
5 0

Answer: 1

Step-by-step explanation:

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I need help with this please. :)
jek_recluse [69]

9514 1404 393

Answer:

  1. 2x
  2. 2
  3. 128x +640

Step-by-step explanation:

1.

  \displaystyle\frac{8x^2-4x}{4x-2}=\frac{4x(2x-1)}{2(2x-1)}=\boxed{2x}

__

2.

  \displaystyle\frac{8x-4}{x+3}-\frac{12x-20}{2x+6}=\frac{8x-4}{x+3}-\frac{4(3x-5)}{2(x+3)}=\frac{8x-4-2(3x-5)}{x+3}\\\\=\frac{8x-4-6x+10}{x+3}=\frac{2x+6}{x+3}=\frac{2(x+3)}{x+3}=\boxed{2}

__

3.

  \displaystyle\frac{(2x+10)^7}{(x+5)^6}=\frac{(2(x+5))^7}{(x+5)^6}=2^7(x+5)^{7-6}=128(x+5)\\\\=\boxed{128x+640}

5 0
3 years ago
1. A soccer field has an area (A = LW) that is represented by the polynomial 1 point
matrenka [14]

Answer:

(x + 6)(x - 6)

Step-by-step explanation:

Given

See attachment for soccer field

Required

The possible dimension of the field

From the attachment, we have:

Area = x^2 - 36

Length = x +a

Width = x + b

So, we have:

Length * Width = Area

This gives:

(x + a)(x + b) = x^2 - 36

Express 36 as 6^2

(x + a)(x + b) = x^2 - 6^2

Express as difference of two squares

(x + a)(x + b) = (x + 6)(x - 6)

Hence, the dimension is: (x + 6)(x - 6)

6 0
3 years ago
The function<img src="https://tex.z-dn.net/?f=f%28x%29%3D-3x%5E%7B3%7D%20%2Bx%5E%7B2%7D%20%2B2x" id="TexFormula1" title="f(x)=-3
musickatia [10]

Answer:

True

Step-by-step explanation:

True.

Like the cubic term -3x^3 is negative, for small values of "x", the dependent variable "y" will rise. All this can be verified by looking at the graph.

6 0
3 years ago
Which system has no solutions?
seraphim [82]

Answer:

2nd option

y > 6 and y < 2

Step-by-step explanation:

as the value of y can not be greater than 6 and less than 2 at the same time, the 2 inequalities have no common solutions

theefore no solution

8 0
3 years ago
Sixty less than ten times ten
Otrada [13]

Answer:

40

Step-by-step explanation:

10x10=100

100-60=40

Hope this helps! :)

3 0
3 years ago
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