Question

Helpenejiriehdisnsjsos​

Answer 1

Answer:

$2 + \sqrt{3}$

Step-by-step explanation:

$\dfrac{1}{\sqrt{4} - \sqrt{3}} =$

$= \dfrac{1}{2 - \sqrt{3}}$

$= \dfrac{1}{2 - \sqrt{3}} \times \dfrac{2 + \sqrt{3}}{2 + \sqrt{3}}$

$= \dfrac{2 + \sqrt{3}}{(2 - \sqrt{3})(2 + \sqrt{3})}$

$= \dfrac{2 + \sqrt{3}}{4 - 3}$

$= \dfrac{2 + \sqrt{3}}{1}$

$= 2 + \sqrt{3}$