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PolarNik [594]
3 years ago
6

What is the area of Triangle II?

Mathematics
1 answer:
Nuetrik [128]3 years ago
8 0

10.5625 is your answer hope i helped

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The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and
Scorpion4ik [409]

Answer:

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

Step-by-step explanation:

The PDF of X is

\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)

The PDF of Y is

\bf g(x)=\mu e^{-\mu x}\;(x\geq0)

The means of X and Y are respectively,

\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

7 0
2 years ago
The diagram is a straightedge and compass construction. A is the center of one circle,
mel-nik [20]

Answer:

All the points are the same distance from the center of line AB, therefore it is just the same triangle but rotated. They are the same triangle .

Step-by-step explanation:

5 0
3 years ago
Square of a binomial x^2+2x+1
garik1379 [7]
To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square. 
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial. 
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2. 
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial. 
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1. 
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
3 0
3 years ago
What's the answer to -6<21
Sphinxa [80]

Answer:

Step-by-step explanation:

There's no answer here. Because -6<21.

5 0
3 years ago
Write a vector equation of the line that passes through point P(-4,11) and is parallel to a=[-3,8]. Then write parametric equati
Assoli18 [71]

Answer:

\vec l = (-4, 11) + t\cdot (-3,8), x = -4 - 3\cdot t and y = 11 + 8\cdot t

Step-by-step explanation:

The vector equation of the line is:

\vec l = \vec P + t \cdot \vec A

\vec l = (-4, 11) + t\cdot (-3,8)

The parametric equations of the line are:

x = -4 - 3\cdot t and y = 11 + 8\cdot t

4 0
3 years ago
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