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2 years ago

The table shows the atomic radii of four elements.

Mathematics

2 answers:

RideAnS [48]2 years ago

7 0

$\sf Potassium \ : \ 2.2 * 10^{-7}$

$\sf Argon \ : \ 7.1 * 10^{-8}$

$\sf Boron \ : \ 8.5 * 10^{-8}$

$\sf Silver \ : \ 1.6 * 10^{-7}$

greatest to least :

Potassium < Silver < Boron < Argon

Korvikt [17]2 years ago

4 0

The order is

Potassium>Silver>Boron>Argon

Shortcut trick :-

The nature of atomic radii in. periodic table

Decrease in a period from left to right.
Increase in a group from up to down

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The formula for converting Celsius temperatures to Fahrenheit temperatures is a linear equation. Water freezes at 0°C, or 32°F a

BlackZzzverrR [31]

Answer:

The formula y = mx + b sometimes appears with

different symbols.

For example, instead of x, we could use the

letter C. Instead of y, we could use the letter F.

Then the equation becomes

F = mC + b.

All temperature scales are related by linear

equations. For example, the temperature in

degrees Fahrenheit is a linear function of degrees Celsius.

Water freezes at: 0°C, 32°F

Water Boils at: 100°C, 212°F

Hope this helps!

4 0

3 years ago

Write the equation. 5 more than a number times 2 is 2

suter [353]

$(5 +n)\cdot2 = 2$

$3(2 -n) > 7$

8 0

3 years ago

The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.

tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that perpendicular lines have negative reciprocal slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

$\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}$

so, it passes through the midpoint of AB,

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)$

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}$