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salantis [7]
2 years ago
9

What are the slope and y - intercept of the equation 6x+3y=-12

Mathematics
1 answer:
sertanlavr [38]2 years ago
4 0

Answer:

Slope= -2

y-intercept= -4

Step-by-step explanation:

To find the slope and y-intercept of a given equation, first rearrange the equation such that it is in the slope-intercept form. In the slope-intercept form, the coefficient of y is 1 and the rest are moved to the left hand side of the equation.

\textcolor{steelblue}{\text{Slope-intercept form}}

  • y= mx +c, where m is the slope and c is the y-intercept

Given equation: 6x +3y= -12

Let's leave the y term on the left of the equation and bring the rest to the right.

3y= -6x -12

To ensure that the coefficient of y is 1, divide both sides by 3.

y= -2x -4

The equation is now in the slope-intercept form.

The slope is the coefficient of x (the number that comes before x), thus the slope is -2. The y-intercept is -4.

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Answer:

\huge\boxed{p(x)=4x^3-20x^2+4x+300}

Step-by-step explanation:

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p(x)=(x^2-2(x)(4)+4^2-3^2i^2)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ i^2=-1\\\\p(x)=(x^2-8x+16-9(-1))(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+16+9)(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+25)(x+3)\bigg(r(x)\bigg)\qquad\text{use FOIL}:\ (a+b)(c+d)=ac+ad+bc+bd\\\\p(x)=\bigg((x^2)(x)+(x^2)(3)+(-8x)(x)+(-8x)(3)+(25)(x)+(25)(3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x^3+3x^2-8x^2-24x+25x+75)\bigg(r(x)\bigg)\qquad\text{combine like terms}\\\\p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)

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±

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