15% of 20 gal = 0.15 * 20 gal = 3 gal, so the solution contains 3 gal of salt.
If we add <em>x</em> gal of water to the solution, we end up with (20 + <em>x</em>) gal of solution. We want the new mixture to have a concentration of 10%, or
10% of (20 + <em>x</em>) gal = 0.1 * (20 + <em>x</em>) gal = 2 + 0.1<em>x</em> gal
of salt.
The amount of salt in the tank hasn't changed. Solve for <em>x </em>:
2 + 0.1<em>x</em> = 3
0.1<em>x</em> = 1
<em>x</em> = 10 gal
Answer:
i think the 2nd one is correct .. i have not fluent in english to explain the answer.
Answer:
(-8 , 3)
Step-by-step explanation:
(x1 , y1) (x2 , y2) = (-10 , -1) (-6 , 7)
, 
-6 is going to be my x1 and -10 my y1
7 is going to be my x2 and -1 my y2
(-8 , 3)
When you have two mutually exclusive events, to find the probability of one or another, you add the probabilities.
65+7=72
Final answer: B
