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geniusboy [140]
2 years ago
10

Suppose that the objective function coefficient for product C increases by $8. What impact will this have on the current values

of the optimal solution
Mathematics
1 answer:
maw [93]2 years ago
6 0

When the objective function coefficient for the product increases by $8, the impact on the current values of the optimal solution is that the current solution will change.

<h3>What is an objective function?</h3>

An objective function simply means the function whose value is to be either maximized or minimized over the alternatives.

In this case, when the objective function coefficient for the product increases by $8, the impact on the current values of the optimal solution is that the current solution will change. The change is due to the varied objectives.

Learn more about objective function on:

brainly.com/question/26100401

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The segments shown below could form a triangle. 4,3,6 PLZ HELP ASAP
Rzqust [24]

Answer:

Option A. True

Step-by-step explanation:

we know that

<u>The Triangle Inequality Theorem</u>, states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

we have

4,3 and 6

Applying the triangle inequality theorem

case 1) 4+3 > 6 -----> is true

case 2) 3+6 > 4 ----> is true

therefore

The given segments could form a triangle

Is true

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3 years ago
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Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).
Serjik [45]

Answer:

\displaystyle f(x)=x^2+2x+2

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

\displaystyle f(x)=ax^2+bx+c

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

\displaystyle f(-1)=a(-1)^2+b(-1)+c

\displaystyle f(-1)=a-b+c

\displaystyle a-b+c=1.....[eq\ 1]

Now we use the second condition f(1)=5

\displaystyle f(1)=a(1)^2+b(1)+c

\displaystyle f(1)=a+b+c

\displaystyle a+b+c=5.......[eq\ 2]

Finally, we use the third condition f(2)=10

\displaystyle f(2)=a(2)^2+b(2)+c

\displaystyle f(2)=4a+2b+c

\displaystyle 4a+2b+c=10....[eq\ 3]

We put together eq 1, eq 2, and eq 3 to form the system

\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.

Adding the first two equations we have

\displaystyle 2a+2c=6

\displaystyle a+c=3

And also

\displaystyle b=2

Using the above equation and the value of b in the third equation, we have

\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.

Subtracting the first equation from the second

\displaystyle 3a=3

\displaystyle a=1

And therefore

\displaystyle c=2

Now we have all the values, the quadratic function is

\displaystyle \boxed{f(x)=x^2+2x+2}

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olasank [31]

Answer:

27 in²

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