Which inequality is equivalent to this one?
2 answers:
<h2>Answer:</h2>
The inequality which is equivalent to the given inequality is:
D.
We are given a inequality as:
which on simplifying gives.
i.e. on adding 8 on both side of the inequality we get:
A)
on simplifying we gets:
which does not matches the actual inequality.
Hence, option: A is incorrect.
B)
on solving we get:
which is not equivalent to the given inequality.
Hence, option: B is incorrect.
C)
on simplifying we get:
Now on adding both side of the inequality by 6 we get:
which again does not matches.
Hence, option: C is incorrect.
D)
on simplifying we get:
It matches the actual expression.
Hence, option: D is correct.
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Answer:
Angle = Ф = (0) = 0
Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.
Step-by-step explanation:
Given vector r(t) =
As we know that,
velocity vector = v =
Implies that
velocity vector =
As acceleration is velocity over time so:
acceleration vector = a =
Implies that
vector a =
vector a =
Now scalar product of position vector r and acceleration vector a:
r. a =
r.a =
r.a = 0
Now, for angle between position vector r and acceleration vector a is given by:
cosФ = =
Ф = (0) = 0
Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.