Question

If the point (x,square root 3/2) is on the unit circle, what. is x?

Answer 1

Answer:

$x=\pm\frac{1}{2}$

Step-by-step explanation:

On a unit circle, $(x,y)=(\cos\theta,\sin\theta)$, so $\sin\theta=\frac{\sqrt{3}}{2}$ in this case. If you look at the attached circle, the only time that the y-coordinate is $\frac{\sqrt{3}}{2}$ is when $x=-\frac{1}{2}$ and $x=\frac{1}{2}$, which correspond to angles of $\theta=\frac{2\pi}{3}$ and $\theta=\frac{\pi}{3}$ respectively