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STALIN [3.7K]
3 years ago
11

What is the difference between bacteria and cancer cells​

Chemistry
2 answers:
Dahasolnce [82]3 years ago
7 0
Las bacterias son microorganismos procariotas que presentan un tamaño de unos pocos micrómetros y diversas formas, incluyendo esferas, barras, filamentos curvados y helicoidales.
Las células cancerosas son células que se dividen sin descanso, formando tumores sólidos o inundando la sangre con células anormales. La mitosis es un proceso normal utilizado por el cuerpo para el crecimiento y la reparación.

Harrizon [31]3 years ago
5 0

Answer:Your body constantly produces new cells. Normal cells follow a typical cycle: They grow, divide and die. Cancer cells, on the other hand, don't follow this cycle. Instead of dying, they multiply and continue to reproduce other abnormal cells.

Explanation:

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Arrange the following in order of increasing bond strength of the carbon oxygen bond: Group of answer choices Carbon monoxide &l
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Answer:

carbonate ion < carbon dioxide < carbon monoxide

Explanation:

Bond strength depends on the bond order of a bond. The higher the bond order, the greater the bond strength since shorter bonds are stronger than longer bonds.

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Since the compound with the highest C-O  bond order has the strongest C-O bond, then carbon monoxide possesses the strongest C-O bond.

3 0
3 years ago
if 3.0 grams of aluminum and 6.0 grams of bromine react to form AlBr3, how many grams of product would theoretically be produced
Gelneren [198K]
1) Chemical reaction: 2Al + 3Br₂ → 2AlBr₃.
m(Al) = 3,0 g.
m(Br₂) = 6,0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 3,0 g ÷ 27 g/mol.
n(Al) = 0,11 mol.
n(Br₂) = n(Br₂) ÷ m(Br₂).
n(Br₂) = 6 g ÷ 160 g/mol.
n(Br₂) = 0,0375 mol; limiting reagens.
n(Br₂) : n(AlBr₃) = 3 : 2.
n(AlBr₃) = 0,025 mol.
m(AlBr₃) = 0,025 mol · 266,7 g/mol.
m(AlBr₃) = 6,67 g.

2) m(Br₂) - all bromine reacts, so mass of bromine after reaction is zero grams (m(Br₂) = 0 g).
n(Al) = 0,11 mol - 0,025 mol = 0,085 mol.
m(Al) = 0,085 mol · 27 g/mol.
m(Al) = 2,295 g.
m(AlBr₃) = 6,67 g · 0,72 (yield of reaction).
m(AlBr₃) = 4,8 g.
n - amount of substance.
M - molar mass.

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