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Savatey [412]
2 years ago
6

Energy transformation of a kettle?

Chemistry
2 answers:
Vika [28.1K]2 years ago
8 0

Explanation:

<h3><em>Energy transformation of a kettle?</em></h3><h3><em>Energy transformation of a kettle?=⟩Electrical energy into heat energy.</em></h3>

<h3><em>hope </em><em>it</em><em> is</em><em> helpful</em><em> to</em><em> </em><em>you </em><em>☺️</em><em>❣️</em><em>❇️</em><em>✌️</em><em>☪️</em><em>☺️</em></h3>
zubka84 [21]2 years ago
6 0

Explanation:

<h3>Electrical energy into heat energy..</h3>

<h2>hope it helps.</h2><h2>stay safe healthy and happy...</h2>
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What is the empirical formula of an oxide of nitrogen containing 63.61% by mass of nitrogen and 36.69% by mass of oxygen?
katen-ka-za [31]

Answer:

D. N₂O

Explanation:

Let's assume we have 100 g of the compound.  That means it consists of 63.61 grams of nitrogen and 36.69 grams of oxygen.

Converting masses to moles:

63.61 g N × (1 mol N / 14.01 g N) = 4.540 mol N

36.69 g O × (1 mol O / 16.00 g O) = 2.293 mol O

Normalize by dividing by the smallest:

4.540 / 2.293 = 1.980 mol N

2.293 / 2.293 = 1.000 mol O

So there is approximately twice as many N atoms as O atoms.  The empirical formula is therefore N₂O.

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How much ice (in grams) would have to melt to lower the temperature of 354 ml of water from 26 ?c to 6 ?c? (assume the density o
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Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:<span>

Heat = mC(T2-T1) 

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<span>Heat gained = Heat lost</span>
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C(liquid water) = 4.18 J/gC
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