Answer:
Using The element calcium Ca, we have
CaO
CaOH
CaCl
Explanation:
The question is incomplete. The complete question is:
A certain molecular compound M has a solubility in acetone of 0.737g/mL at 10.°C
.Calculate the mass of M that's dissolved in 9.0 L of a saturated solution of M in acetone at this temperature.
Be sure your answer has the correct unit symbol and number of significant digits.
Answer: 6633 g of M is dissolved in 9.0 L of saturated solution in hexane at this temperature.
Explanation:
Given : 0.737g of solute is present in 1ml of solution
i.e 1ml of solution contains = 0.737 g of solute
Thus 9L or 9000ml of solution contains=
Thus 6633 g of M is dissolved in 9.0 L of saturated solution in hexane at this temperature.
Answer: OA is a balanced equation.
Explanation: For an equation to be balanced, the number of atoms and the total charge of each element in the reaction, of the product and reactant side must be the same.
Considering OA; 6 atoms of nitrogen is present in the reactant side. Shifting to the product side, 6 atoms of nitrogen is also present. Taking the other element in the reaction into account, the number of atoms of each element balances on both sides.
Answer:3.3
when you plug the [H+] you get..
-log(5x10^-4)
3.3
Answer:
(A) NaOH and Ca(OH)2: Ca(OH)2
(B) MgCl2 and MgF2: MgF2
(C) Agl and KI: AgI
(D) NH4Cl and PbCl2: PbCl2
Explanation:
We need to see the solubility in water, at similar temperatures, for each compound and see which one is less soluble than the other:
NaOH: 1000 g/L (25 °C)
Ca(OH)2: 1.73 g/L (20 °C)
MgCl2: 54.3 g/100 mL (20 °C)
MgF2: 0.013 g/100 mL (20 °C)
Agl: 3×10−7g/100mL (20 °C)
KI: 140 g/100mL (20 °C)
NH4Cl: 383.0 g/L (25 °C)
PbCl2: 10.8 g/L (20 °C)
After the comparison made we can conclude that the less soluble, after saturation of water, will precipitate first.