If -nx2 + tx + c = 0, what is x equal to?

1 answer:

5 0

$f(x)=-nx^2+tx+c=0\\\\
\Delta=t^2-4\cdot(-n)\cdot c=t^2+4cn\\\\
1.\\
 \Delta0\\
\sqrt{\Delta}=\sqrt{t^2+4cn}\\
x_1=\frac{-t-\sqrt{t^2+4cn}}{2\cdot(-n)}=\frac{t+\sqrt{t^2+4cn}}{2n}\\
x_2=\frac{-t+\sqrt{t^2+4cn}}{2\cdot(-n)}=\frac{t-\sqrt{t^2+4cn}}{2n}\\$

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