In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
Only once, any number higher will pass it
The coordinates that you record is an example of data from the graph I think
Answer:
Should be a collective noun.
For example: In addition to those...
F(-1) = 3
How did I figure this out?
f(-1) is substituted for f(x) so you must look at -1 on the x axis.
Once you've located -1 on the x-axis, locate what it equals to answer the question.
The answer should be the y-axis number that corresponds to -1 which is 3.
