Question

The area of the squared garden is 625 sq. m, what is its perimeter ? (Ans: 100 m)​

Answer 1

Answer: Area of square = a*a(where a is length of one side) Putting value a x a=625 cm2 a= 25 Perimeter will be 4 x a 4 x 25 = 100 cm

Step-by-step explanation:

Answer 2

$\sf\huge\underline{Given:-}$

Area of the square field $\sf{= 625 m^2}$

$\sf\huge\underline{To\: Find:-}$

$\rightarrow$ Perimeter of the square garden.

$\sf\huge\underline{Formula \:Used:-}$

Area of square $\sf{= side^2}$

Perimeter of square $\sf{= 4×side}$

$\sf\huge\underline{Solution:-}$

As we know,

$\rightarrow$ Area of square $\sf{= side^2}$(putting the given value of area)

$\rightarrow$ $\sf{Side^2}$ $\sf{= 625}$

$\rightarrow$ $\sf{Side}$$\sf{= \sqrt{625}}$

$\rightarrow$$\sf{Side}$$\sf{= 25cm}$

So, From here we got the side of the square garden that is, 25cm.

Now,

$\rightarrow$Perimeter of square $\sf{= 4×side}$(Putting the value of side)

$\rightarrow$ Perimeter of square $\sf{= 4×25}$

$\rightarrow$Perimeter of square $\sf{= 100cm}$

Therefore, perimeter of the square garden = 100cm.