False<span>, well designed weight training programs actually target most of the muscles in the body. A good weight training program includes many compound exercises to activate multiple muscle groups and promote muscle hypertrophy. Some isolation exercises may also be included to target a specific muscle and help it grow.</span>
Answer:
r = 0.0414mm
F = 757,692.3Hertz
Explanation:
If the body enters space with uniform magnetic field B, the force experienced by the object is expressed as
F = qvBsintheta... 1
Also, if the body undergoes a circular motion, the force experienced by the body in a circular path is given as
Fc = mv²/r... 2
Equating both forces
F = Fc
qvBsin theta = mv²/r
Since the body enters perpendicular to the field, theta = 90°
The equality becomes;
qvB sin90° = mv²/r
qvB = mv²/r
qB = mv/r
r = mv/qB
Given mass of the electron m = 9.11×10^-31kg
Velocity of the object v = 197m/s
Charge on the electron q = 1.6×10^-19C
Magnetic field B = 2.71×10^-5T
Substituting this value into the equation to get the radius r we have;
r = 9.11×10^-31 × 197/1.6×10^-19 × 2.71×10^-5
r = 1794.67×19^-31/4.336×10^-24
r = 413.89×10^-7
r = 0.0000414m
r = 0.0414mm
b) Frequency of the motion F = w/2π where w is the angular velocity
Since w = v/r
F = (v/r)/2π
F = v/2πr
F = 197/2π(0.0000414)
F = 757,692.3Hertz
Answer:
A
Explanation:
Electrons do not orbit the nucleus rather like the planets orbiting the Sun. Electrons do not orbit they are simply used for a microscope, laser, radiation therapy, and electronics.
The total charge passing a given point in the conductor from t = 0 to t = 1/240 s is 12000π Coulombs
<h3>Total charge through a conductor</h3>
A conductor is a substance that allow current and electricity to pass through it.
The expression that will be used to calculate the current is expressed s:
I(t) = 100 sin (120πt)
where
I is in amperes and t is in seconds.
Since dQ = Idt = I(t) = 100 sin (120πt)
On integrating
Q = 100*120πcos(120πt) |¹/¹²⁴⁰₀
Substitute the limits
Q = 100 * 120π
Q = 12000π Coulombs
Hence the total charge passing a given point in the conductor from t = 0 to t = 1/240 s is 12000π Coulombs
Learn more on total charge through a conductor here: brainly.com/question/15083960
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Thus, the car would travel a distance of 50 metres in 4 seconds.
