To develop this problem we will apply the concepts related to Sound Intensity. This can be defined as the power carried by sound waves per unit area in a direction perpendicular to that area. Mathematically it can be written as,

= Level Difference
n = Number of equal loud sound sources
n = 15
Therefore replacing we have,

Therefore over 100dB the total difference intensity level would be

Here,



The intensity level generated by one engine is

D. the value of the star's apparent magnitude increases
Answer:
a)52.58 m/s
b)56.13°
Explanation:
assume the upward direction as positive
x-component of the velocity = 29.3×cos33.6°=24.40 m/s (remain constant)
y-component of the velocity which is -29.3sin33.6°= -16.21 m/s
time of flight = 68.3/24.40= 2.7991 seconds
now, we can obtain final velocity in y-direction


=43.66 m/s

=52.58 m/s
for direction

56.13° from the horizontal
Complete question:
A uniform electric field is created by two parallel plates separated by a
distance of 0.04 m. What is the magnitude of the electric field established
between the plates if the potential of the first plate is +40V and the second
one is -40V?
Answer:
The magnitude of the electric field established between the plates is 2,000 V/m
Explanation:
Given;
distance between two parallel plates, d = 0.04 m
potential between first and second plate, = +40V and -40V respectively
The magnitude of the electric field established between the plates is calculated as;
E = ΔV / d
where;
ΔV is change in potential between two parallel plates;
d is the distance between the plates
ΔV = V₁ -V₂
ΔV = 40 - (-40)
ΔV = 40 + 40
ΔV = 80 V
E = ΔV / d
E = 80 / 0.04
E = 2,000 V/m
Therefore, the magnitude of the electric field established between the plates is 2,000 V/m
Answer:

Explanation:
Here we know that the EMF induced in this Field is given as

here B = perpendicular component of magnetic field
v = speed of the bird
L = length of the wings
now we have



now we have

