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3 years ago

9

The core of a star must be at temperature of _____ degrees Celsius for hydrogen fusion to take place. 10,000 100,000 1,000,000 1

0,000,000 100,000,000

1 answer:

disa [49]3 years ago

6 0

The core of a star must be at the temperature of 10,000,000 degrees Celsius for hydrogen fusion to begin.

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If the intensity level by 15 identical engines in a garage is 100 dB, what is the intensity level generated by each one of these

goblinko [34]

To develop this problem we will apply the concepts related to Sound Intensity. This can be defined as the power carried by sound waves per unit area in a direction perpendicular to that area. Mathematically it can be written as,

$\Delta L = 10log(n)$

$\Delta L$ = Level Difference

n = Number of equal loud sound sources

n = 15

Therefore replacing we have,

$\Delta L = 10 log (n)\\\Delta L = 10 log (15)\\\Delta L = 10*1.176\\\Delta L = 11.76dB$

Therefore over 100dB the total difference intensity level would be

$L_T = L_0 -\Delta L$

Here,

$L_0 = \text{ Total intensity}$

$\L_T = 100 -11.76$

$_T= 88.24dB$

The intensity level generated by one engine is

$L_T = 88.44dB$

8 0

3 years ago

Suppose a star is 500 light- years away from earth is moved to be 600 light - years away. Which statement is correct?

mina [271]

D. the value of the star's apparent magnitude increases

5 0

3 years ago

Read 2 more answers

After leaving the end of a ski ramp, a ski jumper lands downhill at a point that is displaced 68.3 m horizontally from the end o

inessss [21]

Answer:

a)52.58 m/s

b)56.13°

Explanation:

assume the upward direction as positive

x-component of the velocity = 29.3×cos33.6°=24.40 m/s (remain constant)

y-component of the velocity which is -29.3sin33.6°= -16.21 m/s

time of flight = 68.3/24.40= 2.7991 seconds

now, we can obtain final velocity in y-direction

$v_f_y= v_i_y-gt$

$v_f_y=-16.21-(-9.8)×2.7991$

=43.66 m/s

$v_0=\sqrt{29.3^2+43.66^2}$

=52.58 m/s

for direction

$tan^{-1}\frac{43.66}{29.3}$

56.13° from the horizontal

3 0

2 years ago

A uniform electric field is created by two parallel plates separated by a distance of 0.04 m. What is the magnitude of the elect

FromTheMoon [43]

Complete question:

A uniform electric field is created by two parallel plates separated by a

distance of 0.04 m. What is the magnitude of the electric field established

between the plates if the potential of the first plate is +40V and the second

one is -40V?

Answer:

The magnitude of the electric field established between the plates is 2,000 V/m

Explanation:

Given;

distance between two parallel plates, d = 0.04 m

potential between first and second plate, = +40V and -40V respectively

The magnitude of the electric field established between the plates is calculated as;

E = ΔV / d

where;

ΔV is change in potential between two parallel plates;

d is the distance between the plates

ΔV = V₁ -V₂

ΔV = 40 - (-40)

ΔV = 40 + 40

ΔV = 80 V

E = ΔV / d

E = 80 / 0.04

E = 2,000 V/m

Therefore, the magnitude of the electric field established between the plates is 2,000 V/m

7 0

2 years ago

It is known that birds can detect the earth's magnetic field, but the mechanism of how they do this is not known. It has been su

san4es73 [151]

Answer:

$EMF = 5.01 \times 10^{-4} Volts$

Explanation:

Here we know that the EMF induced in this Field is given as

$EMF = vBL$

here B = perpendicular component of magnetic field

v = speed of the bird

L = length of the wings

now we have

$B = 5\times 10^{-5} sin40$

$v = 13 m/s$

$L = 1.2 m$

now we have

$EMF = (13)(3.21 \times 10^{-5})(1.2)$

$EMF = 5.01 \times 10^{-4} Volts$

8 0

3 years ago