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3 years ago

9

The core of a star must be at temperature of _____ degrees Celsius for hydrogen fusion to take place. 10,000 100,000 1,000,000 1

0,000,000 100,000,000

1 answer:

disa [49]3 years ago

6 0

The core of a star must be at the temperature of 10,000,000 degrees Celsius for hydrogen fusion to begin.

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When a guitar is tuned to adjust it pitch what is it that is changed?

suter [353]

Answer:

B) Its frequency

Explanation:

<u>The pitch of sound heard depends on its frequency of the sound wave. Frequency refers to how fast the sound wave is oscillating. </u>
A high frequency sound wave has a high pitch while a low frequency sound wave has a low pitch.
The faster the sound wave oscillates the higher the pitch. For instance, a guitar with a big heavy string will vibrate slowly and thus create a low pitch.

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3 years ago

GIVING BRAINLIEST PLEASE HELP!!

alisha [4.7K]

Answer:

c is the right answer is it

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3 years ago

In a television set the power needed to operate the picture tube comes from the secondary of a transformer. The primary of the t

Natasha2012 [34]

Answer:

c) N_s / N_p = 115.15

Explanation:

Let's look for the voltage in the secondary, they do not indicate the power dissipated

P = V_s i

V_s = P / i

V_s = 76 / 5.5 10⁻³

V_s = 13.818 10³ V

the relationship between the primary and secondary of a transformer is

$\frac{V_p}{N_p} = \frac{V_s}{N_s}$

$\frac{N_s}{N_p} = \frac{V_s}{V_p}$

Ns / Np = 13,818 10³ /120

N_s / N_p = 115.15

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3 years ago

A cardinal (Richmondena cardinalis) of mass 4.00×10−2 kg and a baseball of mass 0.146 kg have the same kinetic energy. What is t

sp2606 [1]

Answer:

0.5232

Explanation:

the cardinal and the baseball has the same kinetic energy

$\frac{1}{2} m_{c} v_{c} ^{2} = \frac{1}{2} m_{b} v_{b} ^{2}$

$m_{c}v_{c}^{2} = m_{b}v_{b}^{2}$

$[4.0X 10^{-2} ]v_{c} ^{2} = [0.146]v_{b} ^{2}$

$\frac{v_{c} }{v_{b} } = \sqrt{\frac{0.146}{4.0 X 10^{-2} } }$

$\frac{v_{c} }{v_{b} } = 1.910$

Ratio of momentum

$\frac{p_{c}}{p_{b}} = \frac{m_{c}v_{c}}{m_{b}v_{b}} = \frac{ (4.0 X 10^{-2} )(1.910v_{b} )}{0.146v_{b} }$

$\frac{p_{c}}{p_{b}} = \frac{4.0 X 10 ^{-2} X 1.910 }{0.146} = 0.5232$

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4 years ago

Where is the sun's energy most concentrated

Maru [420]

B. At the equator

Explanation:

The energy coming from the Sun hits the Earth's surface at different angles, depending on the latitude of the place. The more perpendicular the ray of lights hit the surface, the more the energy transmitted to the Earth's surface, the warmer the location.

The angle at which the ray of lights hit the Earth is related to the latitude: in particular, the ray of lights arrive perpendicular at the equator ( $0^{\circ}$ ), they arrive at larger angle in the United States (which is located at intermediate latitudes) and they arrive at the largest angles at the poles. For this reason, the sun's most energy is concentrated at the equator.

5 0

3 years ago