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mafiozo [28]
2 years ago
9

What would be the best response to the question in the picture above please respond soon. (will give brainliest)

Mathematics
1 answer:
trasher [3.6K]2 years ago
8 0

Answer:

The product of a rational number with an irrational number is an irrational number. To see this assume that x is a rational number and y an irrational number. Then let us assume that the product xy is rational, which means that there are integers a,b such that xy=a/b. But then we obtain y=(1/x)(a/b) which is also rational since the set of rational numbers is closed under multiplication. But this is a contradiction since y was assumed to be an irrational number.

Step-by-step explanation:

Question:Now consider the product of a nonzero rational number and an irrational number. Again, assume x =a/b , where a and b are integers and b ≠ 0. This time let y be an irrational number. If we assume the product x · y is rational, we can set the product equal to m/n, where m and n are integers and n ≠ 0. The steps for solving this equation for y are shown. Based on what we established about the classification of y and using the closure of integers, what does the equation tell you about the type of number y must be for the product to be rational? What conclusion can you now make about the result of multiplying a rational and an irrational number?

Answer:2

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\boxed{ \boxed{{d \:  =   \:  \sqrt{(x_2 \:  -  \: x_1)^{2} \:  +  \: (y_2 \:  -  \: y_1)^{2} } }}}

<h3>______________________</h3>

<h3>We organize the values:</h3>

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______________________

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<h2>Answer: </h2>

\huge{\boxed{ \bold{2 \sqrt{17} \: units }}}

<h3><em><u>MissSpanish</u></em></h3>
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