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snow_tiger [21]
2 years ago
11

PLEASE HELP ILL GIVE FIVE STARS AND GIVE BRAINLIEST AND GIVE THANKS PLEASE HELP

Mathematics
1 answer:
GREYUIT [131]2 years ago
5 0

Answer: X+Y+5

Step-by-step explanation:

There is no single answer you have to write an equation.

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A. f(x) = 2|2| is differentiable overf<br> X<br> B. g(x) = 2 + || is differentiable over<br> -f
kramer

Recall the definition of absolute value:

• If <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>

• If<em> x</em> < 0, then |<em>x</em>| = -<em>x</em>

<em />

(a) Splitting up <em>f(x)</em> = <em>x</em> |<em>x</em>| into similar cases, you have

• <em>f(x)</em> = <em>x</em> ² if <em>x</em> ≥ 0

• <em>f(x)</em> = -<em>x</em> ² if <em>x</em> < 0

Differentiating <em>f</em>, you get

• <em>f '(x)</em> = 2<em>x</em> if <em>x</em> > 0 (note the strict inequality now)

• <em>f '(x)</em> = -2<em>x</em> if <em>x</em> < 0

To get the derivative at <em>x</em> = 0, notice that <em>f '(x)</em> approaches 0 from either side, so <em>f</em> <em>'(x)</em> = 0 if <em>x</em> = 0.

The derivative exists on its entire domain, so <em>f(x)</em> is differentiable everywhere, i.e. over the interval (-∞, ∞).

(b) Similarly splitting up <em>g(x)</em> = <em>x</em> + |<em>x</em>| gives

• <em>g(x)</em> = 2<em>x</em> if <em>x</em> ≥ 0

• <em>g(x)</em> = 0 if <em>x</em> < 0

Differentiating gives

• <em>g'(x)</em> = 2 if <em>x</em> > 0

• <em>g'(x)</em> = 0 if <em>x</em> < 0

but this time the limits of <em>g'(x)</em> as <em>x</em> approaches 0 from either side do not match (the limit from the left is 0 while the limit from the right is 2), so <em>g(x)</em> is differentiable everywhere <u>except</u> <em>x</em> = 0, i.e. over the interval (-∞, 0) ∪ (0, ∞).

5 0
3 years ago
Please helppp answer quick
hoa [83]
Answer is C:1/3

21 total
7/21=1/3
4 0
3 years ago
Correct to 3 significant figures , the value of 18.75-(2.11)²​
garri49 [273]

Answer:3.657            hope this helps

Step-by-step explanation:

8 0
3 years ago
Can you help me out with a question
soldi70 [24.7K]

We have

As we can see in order to find the shaded area of the figure, we only need to calculate the area of a square.

A_{\text{shaded}}=20\times20=400\operatorname{mm}^2

the shaded area is 400 mm^2

6 0
1 year ago
What is the net price if a purchase would have come to 1500 at the regular price but the 3% discount applied to this purchase
Julli [10]

<u>Answer:</u>

The net price of the product is $1445.

<u>Solution:</u>

Given, regular price of a product is $1500 and it has a discount at the rate of 3%

We have to find the final price of the product.

We know that, <em>final product of price = regular price – discount price </em>

Final price of product = 1500 – 3% of 1500

Final price of product = 1500-\frac{3}{100} \times 1500

= 1500 – 3 \times 15 = 1500 – 45

Final price = 1455

Hence, the net price of the product is $1445.

7 0
3 years ago
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