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1 year ago

A package of chocolates contains 3 caramel-

Mathematics

2 answers:

Lera25 [3.4K]1 year ago

8 0

Answer:

P(caramel) = 3/10

P(raspberry) = 1/3

Step-by-step explanation:

Given:

Caramel chocolates = 3
Raspberry chocolates = 3
Fudge chocolates = 4

⇒ Total chocolates = 3 + 3 + 4 = 10

$\sf Probability \ of \ an \ event \ occurring = \dfrac{Number \ of \ ways \ it \ can \ occur}{Total \ number \ of \ possible \ outcomes}$

$\sf \implies P(picking \ caramel \ chocolate) = \dfrac{3}{10}$

If the picked caramel chocolate is NOT replaced then:

Caramel chocolates = 3 - 1 = 2
Raspberry chocolates = 3
Fudge chocolates = 4
Total chocolates = 10 - 1 = 9

$\sf \implies P(picking \ raspberry \ chocolate) = \dfrac39=\dfrac13$

spayn [35]1 year ago

7 0

Answer: 3 out of 19

Step-by-step explanation:

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Answer:

a) ∠A = 82.2° , ∠C = 62.8° , c = 17.01

Step-by-step explanation:

Explanation:-

Step(i):-

Given data ∠B measures 35° and the values of a and b are 19 and 11

∠B = 35° and sides a = 19 and b = 11

By using sine rule

$\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{Sin C} = 2 R$

now we will use

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cross multiplication , we get

$\frac{19 X sin 35}{11} = sinA$

sin A = 0.990

A = sin⁻¹( 0.990) = 82.2°

∠A = 82.2°

Step(ii):-

we know that ∠A +∠B +∠C = 180°

∠C = 180° - ∠A -∠B

∠C = 180° -82.2°-35°

∠C = 62.8°

Step(iii):-

we will use formula

$\frac{b}{sin B} = \frac{c}{Sin C}$

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$\frac{11 X sin (62.8)}{sin 35} = C$

c = 17.01

Final answer:-

∠A = 82.2° , ∠C = 62.8° , c = 17.01

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