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1 year ago

Which statement is true about the graphs shown?

Mathematics

2 answers:

bija089 [108]1 year ago

7 0

That would be c! Hope this helps ;)

iris [78.8K]1 year ago

5 0

I think C but im not sure

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In the rectangle

LekaFEV [45]

In order to form triangle PQT and quadrilateral TQRS, point T must lie on line PS which is 16 cm. long.

If the ratio of PT to TS is 5:3 and the total length of PS is 16, then PT must be 10 and TS must be 6 (10 + 6 =16) and 10:6 is the same ratio as 5:3. Another way to think about it is 5/3 = 10/6.

Now you have all the lengths that you need to find the areas of the quadrilateral and the triangle.

Make sure you draw a diagram of it!!

7 0

2 years ago

Read 2 more answers

Help pls solve no. 16

Mars2501 [29]

B is the answer because 1+3 is 4 4+5 is 9 9+7 is 16 16+9 is 25 25+11 is 36+13 is 49 and so on

5 0

2 years ago

A test requires that you answer either part A or part B. Part A consists of 7 true-false questions, and part B consists of 5 mul

jeka94

Answer: 3253

Step-by-step explanation:

Given : A test requires that you answer either part A or part B.

Part A consists of 7 true-false questions.

i.e. there are 2 choices to answer each question.

Now, the number of ways to answer Part A : $2^7=128$ (1)

Part B consists of 5 multiple-choice questions with one correct answer out of five.

i.e. there are 5 choices to answer each question.

Now, the number of ways to answer Part B : $5^5=3125$ (2)

Now, the number of different ways to completed answer sheets are possible= $128+3125=3253$ [Add (1) and (2) ]

5 0

3 years ago

triangle AMY ~ MEG , AM = 5 MY=7 AY =3. MEG IS A DILATION of AMY by a scale facyor of 1/3. fimd the perimeter of MEG.

Mademuasel [1]

Answer:

Explanation:

From the question, we're told that triangles AMY and MEG are similar. If triangle AMY has sides AM = 5, MY = 7, and AY = 3 then we can find the side lengths of triangle MEG since we're told from the question that it is a dilation of AMY by a scale factor of 1/3.

So all we need to is multiply the corresponding sides of AMY by 1/3, so we'll have;

$\begin{gathered} ME=5\ast\frac{1}{3}=\frac{5}{3} \\ EG=7\ast\frac{1}{3}=\frac{7}{3} \\ MG=3\ast\frac{1}{3}=3 \end{gathered}$

We can then go ahead and find the perimeter of MEG. Note that to find the perimeter of a triangle, we add all the length of its sides;

$\begin{gathered} \text{Perimeter of MEG}=\frac{5}{3}+\frac{7}{3}+3 \\ =\frac{5+7+9}{3} \\ =\frac{21}{3} \\ =7 \end{gathered}$

The perimeter of MEG is 7.

6 0

10 months ago

A square is inscribed in a circle of diameter 12 millimeters. What is the area of the shaded region? A square is inscribed in a

bezimeni [28]

Answer: A. (72π - 144) mm²

<u>Step-by-step explanation:</u>

$A_{shaded}=A_{circle}-A_{square}\\\\\\A_{circle}=\pi \cdot r^2\\.\qquad \ =\pi \bigg(\dfrac{12\sqrt2}{2}\bigg)^2\\\\.\qquad \ =\pi (6\sqrt2)^2\\.\qquad \ =72\pi\\\\\\A_{square}=side^2\\.\qquad \quad =\dfrac{12\sqrt2}{\sqrt2}^2\\\\.\qquad \quad =12^2\\\\.\qquad \quad =144\\\\\\\large\boxed{A_{shaded}=72\pi-144}$

7 0

2 years ago