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Irina-Kira [14]
2 years ago
10

The Fruitz fruit and vegetable shop is selling grapes at a price which is 10% cheaper than the Happy Fruiterer fruit and vegetab

le shop. A customer bought “n” kilograms of grapes from the Fruitz shop for $50.
a) How much would this $50 worth of grapes cost had he bought the grapes from the Happy Fruiterer?

b) The Happy Fruiterer wants to be competitive so for the coming week, he discounts the grapes by 5% and the following week, discounts them a further 5%. How much would the grapes originally bought for $50 from Fruitz cost during this second week of discounting at the Happy Fruiterer?

c) Which shop is the cheapest during this second week of discounting and by how much?

Please show working out/step-by-step examples!
Mathematics
1 answer:
sdas [7]2 years ago
8 0

Answer:

(a) It costs $55 at Happy Fruiterer

(b) It will cost $49.64

(c) It is cheaper at Happy Fruiterer the second week

Step-by-step explanation:

Since Fruitz shop sells as 10% less than Happy Fruiterer at $50

10% more of $50 = 50 × 10/100 + 50

= $5 + $50 = $55

(a) n Kg of grapes will cost $55 at Happy Fruiterer

(b) if Happy Fruits discounts $55 by 5%, we will have

55 × 5/100 = 2.75

that is $55 - $2.75 = $52.25

If it is discounted further at 5% more the following week, we will have

$52.25 × 5/100 = $2.6125

≈ $2.61

Then the new price for the 2nd week is $52.25 - $2.61

= $49.64

(c) at the second wee of discounting, Fruitz shop still sells at $50 will Happy Fruiterer now see at $49.64. Therefore, it is cheaper at Happy Fruiterer

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Prime Factorization of 64

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The Expression in simplest form is

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Step-by-step explanation:

Simplify:

\sqrt{\dfrac{576}{64} }

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Prime Factorization of 576

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Prime Factorization of 64

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<h3>What is a probability?</h3>

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In this problem:

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