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2 years ago

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Mathematics

1 answer:

BabaBlast [244]2 years ago

3 0

Hey there!

Finding something that’s equivalent to: 4m - 20

Option A.
4(m - 5)

= 4(m) + 4(-5)

= 4m - 20

Possibly Option A. is your answer.

Option B.
2(2m - 10)

= 2(2m) + 2(-10)

= 4m - 20

Possibly Option B. could be your answer

Option C.
4(m - 20)

= 4(m) + 4(-20)

= 4m - 80

Optipn C. isn’t your answer

Option D.
2(2m - 20)

= 2(2m) + 2(-20)

= 4m - 40

Option D. also isn’t your answer just like Option C.

FACTORS OF: 4m - 20

4: 1,2,4, & m

20: 1,2,4,5,10,& 20

LIKE TERMS: 1,2,4

GCF: 4

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

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To a higher number the six changes value in this number above

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The circumference of a sphere was measured to be 80 cm with a possible error of 0.5 cm. A) Use differentials to estimate the max

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Answer:

A) The maximum error in the calculated surface area: $25cm^2$

Relative error: $0.013$

B) The maximum error in the calculated volume: $162cm^2$

Relative error: $0.019$

Step-by-step explanation:

A) The formula for the surface area is:

$A=4\pi r^2$

The measured value is the circumference which is equal to:

$C=2\pi r$

then the radius is:

$r=\frac{C}{2\pi}$

Substituting in the formula of the surface:

$A=4\pi(\frac{C}{2\pi})^2\\A=4\pi(\frac{C^2}{4\pi^2})\\A=\frac{C^2}{\pi}$

Using the formula to calculate the error:

$dy=f'(x)dx$

Where $x$ is the variable measured and $y$ is a function of $x$ ( $y=f(x)$ ).

$dA=f'(C)dC\\dA=\frac{2C^{(2-1)}}{\pi}dC\\dA=\frac{2C}{\pi}dC$

We have C=80cm and dC=0.5cm

$dA=\frac{2C}{\pi}dC\\dA=\frac{2(80)}{\pi}(0.5)\\dA=\frac{160}{\pi}(0.5)\\dA=50.9296(0.5)\\dA=25.4648\approx25cm^2$

The relative error is the maximum error divide by the total area. The total area is: $A=\frac{C^2}{\pi}=\frac{(80)^2}{\pi}=\frac{6400}{\pi}=2037.1833cm^2$

$\frac{dA}{A}=\frac{25.4648}{2037.1833} =0.0125\approx0.013$

B) The formula for the volume is:

$V=\frac{4}{3} \pi r^3$

Using $r=\frac{C}{2\pi}$

$V=\frac{4}{3} \pi r^3\\V=\frac{4}{3} \pi (\frac{C}{2\pi})^3\\V=\frac{4}{3} \pi (\frac{C^3}{8\pi^3})\\V=\frac{1}{3}(\frac{C^3}{2\pi^2})\\V=\frac{C^3}{6\pi^2}$

The maximum error is:

$dV=\frac{3C^{3-1}}{6\pi^2}dC\\dV=\frac{C^{2}}{2\pi^2}dC\\dV=\frac{(80)^{2}}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=(324.2278)(0.5)\\dV=162.1139\approx162cm^2$

The calculated volume is:

$V=\frac{C^3}{6\pi^2}\\V=\frac{(80)^3}{6\pi^2}\\V=\frac{512000}{6\pi^2}\\V=8646.0743$

The relative error is:

$\frac{dV}{V}=\frac{162.1139}{8646.0743}=0.0188\approx0.019$

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Step-by-step explanation:

To determine the amount of vitamin C in each serving of fruit juice, knowing that the bottle of orange juice contains 750 mg of vitamin C and 6 servings, while the bottle of cranberry juice contains 135 mg and 1.5 servings, you must perform the following calculation:

Orange: 750/6

Orange: 125 mg per serving

Cranberry: 135 / 1.5

Cranberry: 90 mg per serving

Thus, the bottle of orange juice will have higher amounts of vitamin C per serving, as it will have 125 mg against 90 mg of the cranberry juice.

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