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JulijaS [17]
3 years ago
8

A bag contains yellow marbles and red marbles, 23 in total. The number of yellow marbles is 4 less than 2 times the number of re

d marbles. How many yellow marbles are there?
Mathematics
1 answer:
Orlov [11]3 years ago
3 0
First let’s express the total number of marbles as such:
y(yellow marbles) + r(red marbles)=23; y+r=23

now let’s express the relation of yellow marbles to red marbles:
y=2r(2 times red marbles) - 4(4 less marbles); y=2r-4

since we figured out what y equals, we can plug into the first equation we created:
(2r-4)+r=23

now solve for r:
2r-4+r=23
combine like terms
3r-4=23
add 4 to both sides
3r=27
divide both side by 3
r=9

plug r back into first equation and solve for y:
y+9=23
subtract 9
y=14

there are 9 red marbles and 14 yellow marbles!


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Answer:

\textsf{A)} \quad 5u^3-2u^2+5u+8

Step-by-step explanation:

Given expression:

(-2u^3+5u-1)+(7u^3-2u^2+9)

Remove parentheses:

\implies -2u^3+5u-1+7u^3-2u^2+9

Collect like terms:

\implies -2u^3+7u^3-2u^2+5u-1+9

Combine like terms:

\implies 5u^3-2u^2+5u+8

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2 years ago
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25 is the number. Hope this helps.
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3 years ago
2. Determine the sum of the first 400 ODD numbers.<br><br>​
il63 [147K]

Odd numbers take the form 2n-1, where n\ge1 is an integer. When n=400, the last odd number would be 799. So we're adding

S=1+3+5+\cdots+795+797+799

By reversing the order of terms, we have

S=799+797+795+\cdots+5+3+1

and we can pair up terms in both sums at the same position to write

2S=(1+799)+(3+797)+(5+795)+\cdots(795+5)+(797+3)+(799+1)

so that we are basically adding 400 copies of 800, and from there we can find the value of the sum right away:

2S=400\cdot800\implies S=160,000

###

We could also make use of the formulas,

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2

We have

S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000

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3 years ago
Beverage A and Beverage B are sold in identical cans. Beverage A is 6% sugar. The portion of Beverage B that is sugar is 0.21. H
muminat

Answer:

3.5 more times sugar in B

Step-by-step explanation:

We need to see that the fact that Beverage B is 0.21 sugar can be translated to percentages, just by multiplying and dividing by 100 to get it easier to see:

0.21 * 100 /100 =  21/100 = 21% percent

This means that for every 100 units, 21 are sugar.

Now we can compare percentages directly, as both have the same volume because are sold in identical cans. We need to get how many times is 21 greater than 6. The only thing we need to do is the ratio between them:

21/6= 3.5

This implies that 21 is 3.5 greater than 6, you can verify it by multiplying 6 by 3.5 and getting 21.

So, B has 3.5 times more sugar than A.

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Step-by-step explanation:

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