Question

Find the missing side of the triangle. I'll mark brainiest please help!

Answer 1

$\huge \underline\text{ Hello There}$

$\text{We know, Pythagoras Theorem}$

$\implies \text{ (Hypotenuse)²= (Base)² + (Altitude)²}$

$\text{Here, \red{Hypotenuse}= x, \red{Base}= 7, \red{Altitude}= 12}$

$\underline \text{To Find, } \text{Value of'x'}$

$\huge \underline\text \red {Solution}$

$\implies {x}^{2} = (7) {}^{2} + {(12)}^{2} \\ \implies(x) {}^{2} = 49 + 144 \\ \implies( {x})^{2} = 193 \\ \implies x = \sqrt{193}$

$\therefore \text{Hypotenuse}= \sqrt{ 193} \text{ km}$

$\text{Correct Opt. C}= \sqrt{ 193} \text{ km}$

Answer 2

Answer:

○ $\displaystyle \textcolor{black}{C.}\:\sqrt{193}\:km.$

Step-by-step explanation:

Use the Pythagorean Theorem to define the hypotenuse:

$\displaystyle a^2 + b^2 = c^2 \\ \\ 7^2 + 12^2 = x^2 \hookrightarrow 49 + 144 = x^2 \hookrightarrow \sqrt{193} = \sqrt{x^2} \\ \\ \boxed{\sqrt{193} = x}$

I am joyous to assist you at any time.