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Vesnalui [34]
3 years ago
6

Algebra 2 question please help me

Mathematics
1 answer:
ss7ja [257]3 years ago
7 0

Answer: I feel the answer is the 1st option, i.e., option A


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Chelsea has four hours of free time on Saturday. She would like to spend no more than 2/3 of an hour on each activity. How many
Galina-37 [17]
Namely, how many times 2/3 goes into 4, well, let's just divide them then

\bf \cfrac{\stackrel{\textit{total hours}}{4}}{\stackrel{\textit{hours per activity}}{\frac{2}{3}}}\implies \cfrac{\quad \frac{4}{1}\quad }{\frac{2}{3}}\implies \cfrac{4}{1}\cdot \cfrac{3}{2}\implies \cfrac{12}{2}\implies 6
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3 years ago
What is the answer??? <br> If you answer it right I will give brainlist I promise <br> Answer ASAP!!
eimsori [14]

Answer:

3

Step-by-step explanation:

3 under each

4 0
2 years ago
Solve x4 − 7x2 − 18 = 0
babunello [35]
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5 0
3 years ago
Read 2 more answers
Find the value of 1/3 divided by 1/2
Arisa [49]

When dividing two fractions, it is important to know to multiply the first fraction by the reciprocal of the second fraction.

Reciprocal means basically a flipped fraction. 2/3 as a reciprocal is 3/2, etc.

1/3 / 1/2= 1/3 x 2/1=2/3

8 0
2 years ago
[Systems of equations] (/20) 1. Suppose the coefficient matrix of a system of linear equations has a pivot position in every row
Marina86 [1]

Answer:

The system is consistent because the rightmost column of the augmented matrix is not a pivot column.

Step-by-step explanation:

It is given that the coefficient of the matrix of a linear equation has a pivot position in every row.

It is provided by the Existence and Uniqueness theorem that linear system is said to be consistent when only  the column in the rightmost of the matrix which is augmented is not a pivot column.

When the linear system is considered consistent, then every solution set consists of either unique solution where there will be no any variables which are free or infinitely many solutions, when there is at least one free variable. This explains why the system is consistent.

For any m x n augmented matrix of any system, if its co-efficient matrix has a pivot position in every row, then there will never be a row of the form [0 .... 0 b].

6 0
3 years ago
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