Answer: 
Step-by-step explanation:
Using the values 
and 
, the slope is 
.
So, the equation is:
Answer:
Step-by-step explanation:
6⁻︎¹(4⁻︎²)
1/6x1/4 2
1/6 x 1/16
1/96
Answer:
C. 2.
Step-by-step explanation:
The graph descends from the left so the coefficient of the leading term is negative. It is also a cubic equation with zeros of -20, about 6.5 and about 13. so we can write the equation as below. The last 2 values can only be guessed because the x axis only shows values which are multiples of 5.
f(x) = a(x + 20)(x - 6.5)(x - 13) where a is a negative constant.
(This is only an approximation).
By the Remainder theorem, when the expression is divided by (x + 10):
f(-10) = -20 so we have
-20 = a (-10 + 20)(-10-6.5)(-10 - 13)
(10)(-16.5)(-23)a = -20
a = -20 / (10)(-16.5)(-23)
a = -0.0053
When the equation is divided by (x - 10) then f(10) is the remainder so substituting we have as the remainder:
-0.0053(10+20)(10-6.5)(10 -13)
-0.0053 * 30 * 3.5 * -3
= 1.7 approximately.
Looks like the answer is 2.
Answer:
- h(x) = -2x^2 -x +3
- Reservoir A releases the same amount of water as Reservoir B over 1 week
Step-by-step explanation:
<u>Given</u>:
f(x) = x^2 -7x +5
g(x) = 3x^2 -6x +2
h(x) = f(x) -g(x)
<u>Find</u>:
h(x)
h(1)
<u>Solution</u>:
The expression for h(x) is found by evaluating its definition:
h(x) = (x^2 -7x +5) -(3x^2 -6x +2)
h(x) = x^2(1 -3) +x(-7 -(-6)) +(5 -2)
h(x) = -2x^2 -x +3
Then h(1) is found by substituting 1 for x:
h(1) = -2(1^2) -(1) +3 = -2 -1 +3
h(1) = 0 . . . . difference in release amounts after 1 week is 0
The true statements are ...
- h(x) = -2x^2 -x +3
- Reservoir A releases the same amount of water as Reservoir B over 1 week
Answer:
10
Step-by-step explanation:
not sure please verify
