2 years ago

A triangles has two sides of lengths 4 and 15 What value could the length of the third side be

Mathematics

1 answer:

Aleks [24]2 years ago

3 0

Answer:in apex it's 12, 15, 13

You might be interested in

What is 3/4•1 <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%20%5Ctimes%204" id="TexFormula1" title=" \frac

OLEGan [10]

The answer for this problem is 3

7 0

3 years ago

Read 2 more answers

Factoring: All Techniques Combined

Ber [7]

$x^{6} + 2 x^{4} - 16 x^{2} - 32 =x^4(x^2+2)-16(x^2+2)=(x^2+2)(x^4-16)=\\ \\=(x^2+2)(x^4-4^2)=(x^2+2)(x^2-4)(x^2+4) =\\ \\=(x^2+2)(x^2+4)(x+2)(x-2) \\ \\ \\a^2-b^2 =(a-b)(a+b)$

8 0

2 years ago

Solve the equation for a. 3a+13.61=−9.43

snow_tiger [21]

Answer: a = -7.68

STEPS:

- Subtract 13.61 from both sides

- Simplify

- Divide both sides by 3

4 0

2 years ago

What is the equation of the line?

kompoz [17]

A line has an equation of a form,

$y=ax+b$

From a graph we can pick two points on the line, say A and B where,

$A(x_1,y_2),B(x_2,y_2)\longrightarrow A(0,0),B(1,-1)$

Using their coordinates we are able to calculate slope.

$a=\dfrac{\Delta{y}}{\Delta{x}}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-1-0}{1-0}=-1$

Hence,

$y=-1\cdot x+b$

The x and y terms can be replaced with coordinates of one point either A or B. I'll pick A.

$0=-1\cdot0+b$

And now solve for b.

$0=0+b\Longrightarrow b=0$

Hence,

$y=-1\cdot x+0$

Simply,

$\boxed{y=-x}$

Hope this helps.

r3t40

8 0

3 years ago

What is the constant term in (2x+9)(x-4)(x+5)

andrezito [222]

Answer:

$-180$

Step-by-step explanation:

$\left(2x+9\right)\left(x-4\right)\left(x+5\right)$

$\left(2x^2+x-36\right)\left(x+5\right)$

$2x^3+11x^2-31x-180$

6 0

2 years ago

Read 2 more answers