2 and -12 are the coordinates of p
Answer:
Expected project duration is determined as a direct result of computing the earliest starting and finishing times for the activities of a project network.
Step-by-step explanation:
In project management, early start is the earliest moment at which a specific activity may start and early finish the earliest moment at which it can end. Early finish (es) is computed as:
EF = ES + d
where d is the activity duration and ES early start
Early start is computed as
ES: Max (EF-1)
or the maximum early start of predecessory activities.
Once we have calculated these values in the network for each activity , the early finish of last activity corresponds to the expected project duration, the earliest time in which we may finish the project if there are no issues.
Max project duration is open question as we could have infinite delays or never finish the project. Time variance in project duration may only be estimated once we have actual execution times of our project.
Slack time and critical path are obtained after obtaining the ES and EF but this info alone is not sufficient. We require either the late start or the late finish of the activities to calculate slack, Zaero slack activities, those that cannot be delayed form critical path and can only be obtained after having ES. EF. LS and LF
Subtract 9a^2-6a+59a 2 −6a+59, a, squared, minus, 6, a, plus, 5 from 10a^2+3a+2510a 2 +3a+2510, a, squared, plus, 3, a, plus, 25
nasty-shy [4]
Answer:
The answer to your question is a² + 9a + 20
Step-by-step explanation:
10a² + 3a + 25 - (9a² - 6a + 5)
- Remove parentheses changing the sign of the second polynomial
10a² + 3a + 25 - 9a² + 6a - 5
- Group like terms
(10a² - 9a²) + (3a + 6a) + (25 - 5)
- Simplify and result
a² + 9a + 20
Answer:
1) First, add or subtract both sides of the linear equation by the same number.
2) Secondly, multiply or divide both sides of the linear equation by the same number.
3)* Instead of step #2, always multiply both sides of the equation by the reciprocal of the coefficient of the variable.
Step-by-step explanation:
I think the correct answer from the choices listed above is option D. For the function f(x) = (x − 2)2 + 4, the <span>vertex is (2, 4), the domain is all real numbers, and the range is y ≥ 4. The domain is all x-values available for the function and the range are the y values and in this case it should be greater than or equal to 4. Hope this answers the question.</span>
