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Darina [25.2K]
2 years ago
11

Jill has a small treasure box

Mathematics
1 answer:
zmey [24]2 years ago
4 0
Jill has a small treasure box
=small treasure box in possession of jill
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Please factor completely: <br><br> 20x^2 - 102x + 54
Temka [501]

Answer:

The answer to your question is 2(x - 9/2)(x - 3/5)

Step-by-step explanation:

Polynomial           20x² - 102x + 54

Process

1.- Find the Greatest Common Factor

                            20   102   54   2

                             10     51    27  2

                              5      51    27  3

                              5      17      9  3

                              5       17     3  3

                              5       17      1  5

                               1       17         17

                                         1

GCF = 2

2.- Factor 2

                        2(10x² - 51x + 27)

3.- Factor   10x² - 51x + 27

Use the general formula to solve this equation

                        x = \frac{-b +- \sqrt{b^{2} - 4ac}}{2a}

a = 10   b = -51   c = 27

                        x = \frac{51 +- \sqrt{51^{2} -4(10)(27)}}{2(10)}

-Simplification

                       x = \frac{51 +- 39}{20}

-Result

                        x₁ = 9/2       x₂ = 3/5

                       (x - 9/2)        (x - 3/5)

4.- Answer

                      2(x - 9/2)(x - 3/5)                              

5 0
2 years ago
The store has sold 90 notebooks which is 20% of all the notebooks they had how many notebooks did the store have at first
kirill115 [55]
90 is 20% so

90 x 5 = 450 note books
4 0
3 years ago
True or false -3&gt;7(1)-10
zubka84 [21]

Answer:

false

Step-by-step explanation:

7(1)-10=-3

which means -3=7(1)-10

5 0
3 years ago
Write a quadratic equation in standard form with x-intercepts (-3, 0) and (4, 0) that passes through (2, -20).
jeka57 [31]

Answer:

The equation in standard form is: y=2x^2-2x-24

Step-by-step explanation:

Since they give you the x-intercepts (the zeros of the quadratic expression) one knows that the binomials: (x-(-3)) and (x-4) must be factors of the quadratic expression.

We can therefore write the equation as:

y=k\,(x+3)(x-4)

using the binomial factors given above, and a numerical factor "k" that we can determine by using the information that the graph passes through the point (2,-20):

y=k\,(x+3)(x-4)\\-20=k\,(2+3)(2-4)\\-20=k\,(5)(-2)\\-20=k\,(-10)\\k=\frac{-20}{-10} \\k=2

Then,the equation can be written as:

y=2\,(x+3)(x-4)\\y=2(x^2-x-12)\\y=2x^2-2x-24

where we wrote the equation already in standard form

5 0
2 years ago
Don't be childish I will report thanks ​
Leya [2.2K]

Answer:

I got no solution :0

7 0
2 years ago
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