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3 years ago

7

Pam has monthly mortgage payment of $750. Her annual property taxes are $1200,her PMI is $55/month, and her homeowners insurance

is $800 per year. How much is deposited into Pam’s escrow account each month?

1 answer:

Alenkinab [10]3 years ago

7 0

Answer:

$100 + $66.67 + $55 = $221.67/month, which is the amount that must be deposited into Pam's escrow account each month....

Step-by-step explanation:

Pam's annual taxes are $1200 per year. It means her escrow each month needs to have 1/12 of that amount. 1200/12 = $100 per month

Her homeowner's insurance is $800 per year, that's 1/12 of that needs to be in her escrow account each month:

$800 / 12, or $66.67/month.

And PMI is $55/month

Add these three together:

$100 + $66.67 + $55 = $221.67/month, which is the amount that must be deposited into Pam's escrow account each month....

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Which of the following sequences are not geometric? (check all that apply) a. 2,10,50,250,1250 b. 1,4,9,16,25,36 c. -4,-2,-1,-0.

Romashka [77]

A is geometric because each number is multiplied by 5.

B is not geometric because it is an arithmetic sequence.

C is a geometric sequence because each number is divided by 2.

D is neither geometric not arithmetic because there is no common ratio and there is not a pattern being added or subtracted to each number.

So, your answer should be B and D.

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3 years ago

Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi

bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

$L = L_{1} + L_{2} + L_{3}$

In which $L_{1}, L_{2}$ and $L_{3}$ are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

$E = E_{1} + E_{2} + E_{3}$

In which $E_{1},E_{2}$ and $E_{3}$ are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

$6*0.050mg = 0.30mg$ of levonorgestrel and $6*0.030mg = 0.18mg$ of ethinyl estradiol are taken.

So $L_{1} = 0.30$ and $E_{1} = 0.18$

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

$5*0.075mg = 0.375mg$ of levonorgestrel and $5*0.040mg = 0.20mg$ of ethinyl estradiol are taken.

So $L_{2} = 0.375$ and $E_{2} = 0.20$

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

$10*0.125mg = 1.25mg$ of levonorgestrel and $10*0.030mg = 0.30mg$ of ethinyl estradiol are taken.

So $L_{3} = 1.25$ and $E_{3} = 0.30$

The total milligrams of levonorgestrel is:

$L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925$

The total milligrams of ethinyl estradiol is:

$E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68$

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0

3 years ago

a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no

Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

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3 years ago

Mrs. Ishimitsu is installing a rubber bumper around the edge of her coffee table. The dimensions of the rectangular table are (2

ollegr [7]

Answer:

$2x^2+8x-30$ represents the total perimeter of the table, and if x = 3 the lentgh of entire rubber bumper is 12 feet.

Step-by-step explanation:

Perimeter is defined as the sum of sides.

For a rectangle having dimension length 'L' and breadth 'B' Since, rectangle has two sides equal.

Perimeter of rectangle = 2 ( length + breadth )

Here, given rectangle has dimension

Length = $2x^2-16$ and breadth = $-x^2+4x+1$

Thus, perimeter of rectangle = $2(2x^2-16+(-x^2+4x+1))$

$=2(2x^2-16-x^2+4x+1)$

$=2(x^2+4x-15)$

$=2x^2+8x-30$

Thus, perimeter of rectangle is $2x^2+8x-30$ ........(1)

Perimeter of rectangle , when x = 3,

Put x= 3 in (1) ,

$2x^2+8x-30\Rightarrow 2(3)^2+8(3)-30 \Rightarrow 18+24-30=12$

Thus, $2x^2+8x-30$ represents the total perimeter of the table, and if x = 3 the lentgh of entire rubber bumper is 12 feet.

5 0

3 years ago

Read 2 more answers