Based on the population mean, the mean of the distribution sample means would be 204.6. The standard deviation would be 0.22.
<h3>What are the mean and standard deviation of the distribution?</h3>
The mean of the distribution sample means is the same as the population means which is 204.6.
The standard deviation can be found as:
σₓ = σ / √n
= 3.1 / √197
= 0.22
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X=21 and y=14
Here is how I got it I found out the ratio of the sides that measured 18 and 12
the ratio was 3:2 so I divided 27 by 1 1/2 and I got 18 but since the equation for x was x-3 all i had to do was 21-3=18 so x=21 and i did the same thing with Y
Answer:
The insurance costs to send goods valued at $16,400 is $410
Step-by-step explanation:
The amount it costs an exporter to insure goods to send overseas = (5/2)% of the value of the goods
Therefore;
The insurance costs, 'C' to send goods valued at $16,400 is given as follows;
C = $16,400 × (5/2)/100 = $410
The insurance costs to send goods valued at $16,400 = $410
Answer:
Can you take a better picture plz because I can’t see the pic.
Step-by-step explanation:
Answer:
82 years and 3 quarters
Step-by-step explanation:
A = P (1 + r / n)ⁿˣ
P = Principal amount
r = Annual interest rate
n = Number of compounds per year
x = time in years
A = Amount after time 'x'
10500 = 2100 (1 + 0.0195 / 4)⁴ˣ
Divide the whole equation by 2100
10500 / 2100 = ({2100 (1 + 0.004875)} / 2100 )⁴ˣ
5 = (1.004875)⁴ˣ
Taking Natural logarithm (㏑) on both sides
㏑ 5 = ㏑ (1.004875)⁴ˣ
㏑ 5 = 4x ㏑ (1.004875)
1.6094 = 4x (0.004863)
1.6094 = 0.01945x
x = 82.75
So, If compounded quarterly at an APR of 1.95% the amount deposited in savings account of $2100 will accumulate to $10500 in 82 years and 3 quarters.