Answer:
<em>The</em><em> </em><em>final</em><em> </em><em>velocity</em><em> </em><em>would</em><em> </em><em>be</em><em> </em><em>5</em><em>0</em><em> </em><em>m</em><em>/</em><em>s</em><em>.</em>
<em>Its</em><em> </em><em>by</em><em> </em><em>formula</em><em>,</em><em> </em>
<em></em>
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer is C
I did it before
The sample size must be 543 so the sample proportion is will not differ by 5%
We are given the following in the question:
Margin of error = 5%
Confidence interval:
p ±z√(p'(1 - p')/n)
Margin of error =
p = ±z√(p'(1 - p')/n)
Since no particular proportion is given, we take
p' = 0.5
Z critical at α 0.02 is ± 2.33
Putting values, we get,
p = ±z√(p'(1 - p')/n)
2.33 x √(0.5(1 - 0.5)/n)
√n = 2.33x 0.5/0.05
n = 542.89 = 543
Thus, the sample size must be 543 so the sample proportion is will not differ by 5%
To learn more about confidence interval refer here
brainly.com/question/15712887
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