There are 10 seniors in the class, from which 4 should be chosen by the teacher. The order of the chosen students does not matter. This means that we speak of combinations. THe equation for calculating the number of possible combinations is:
C=N!/R!(N-R), where N is the total number of objects and R is the number of objects we select from the N
In our case, N=10, R=4.
C= 10!/4!*6!=10*9*8*7*6!/6!*4*3*2*1=<span>10*9*8*7/24=5040/24=210
There are 210 different ways for the teacher to choose 4 seniors in no particular order.</span>
System B has no solution.
There are 4 reds out of 10 so the probability for a red would be 4/10 and for a yellow it would be 1/10. multiply them together to get 4/100 so your probability would be 1/25 or 0.04 or 4%
Answer:
16.5 year
Step-by-step explanation:
Using, mean = sum/no. *of observations
Here,
=> 16.2 = (sum of ages of boys)/18
=> 16.2 x 18 = sum of ages of boys
=> 291.6 = sum of ages of boys
Similarly, sum of ages of girls = 27 x 16.7 = 450.9
Mean(total) = (sumof agesof boys + girls)/45
Mean = (291.6 + 450.9)/45 = 16.5
