Switch where the x and y are, then solve for y. f(x) = y.
x = 3y^2 + 6
x-6 = 3y^2
(x-6)/3 = y^2
f^-1(x) = y = sqrt((x-6)/3)
Nikita's value is 4 times less than Bettina's value. I believe this is the answer.
The degree of the polynomial will tell you the max amount of zeros you will have. 11 in this case.
However you can also have 9,7,5,3,1 (keep subtracting by 2)
So the answer is 1.
Answer:
- <em>The net change in how many bags are on the shelf, from the beginning of Tuesday to the end of Monday is -</em><u>2.</u>
Explanation:
The change in the number of bags any day is the number of bags is equal to the number of bags purchased to restock less the number of bags sold that day.
- Change = bags purchased to restock - bags sold
At the end of <em>Tuesday</em>, the change is:
- Change: 6 - 5 = 1 (note that this means that the number of bags increases by 1)
At the end of <em>Wednesday</em>, the change is:
- Change: 12 - 8 = 4 (the number of bags increases by 4)
At the end of <em>Thursday</em>, the change is:
- Change: 12 - 2 = 10 (the number of bags increases by 10)
At the end of <em>Friday</em>, the change is:
- Change: 18 - 19 = - 1 (the number of bags decreases by 1).
At the end of <em>Saturday</em>, the change is:
- Change: 24 - 22 = 2 (the number of bags increases by 2).
At the end of <em>Sunday</em>, the change is:
- Change: 0 - 15 = - 15 (the number of bags decreases by 15).
At the end of <u>Monday</u>, the change is:
- Change: 0 - 3 = - 3 (the number of bags decreases by 3).
The net change in how many bags are on the shelf, from the beginning of Tuesday to the end of Monday equals the algebraic sum of every change:
- Net change = 1 + 4 + 10 + (-1) + 2 + (-15) + (-3)
- Using associative property: (1 + 4 + 10 + 2) - (1 + 15 +3)
- Simplifying: 17 - 19 = -2
<u>Conclusion</u>: the net change in how many bags are on the shelf, from the beginning of Tuesday to the end of Monday is -2, meaning that the number of bags, after taking into account all sales and restock, decreases by 2.
