Answer:
the electric field and the electric potential increase 5 times
Explanation:
The electric field created by a point charge is
E = k q / r²
in this case the charge changes from q₁ = 1 10⁺⁰ C to q₂ = 5 10⁻⁹ C
with the electric field is proportional to the charge
E₅ = 5 E₁
the electrical power for a point charge is
V = k q / r
as the electric power is proportional to the charge
V₅ = 5 V₁
consequently both the electric field and the electric potential increase 5 times
Answer:
θ = 41.8º
Explanation:
This is an internal total reflection exercise, the equation that describes this process is
sin θ = n₂ / n₁
where n₂ is the index of the incident medium and n₁ the other medium must be met n₁> n₂
θ = sin⁻¹ n₂ / n₁
let's calculate
θ = sin⁻¹ (1.00 / 1.50)
θ = 41.8º
Answer
From the question we can see that the in medium 1 speed of light is 200,000 Km/s where as in Medium 2 speed of light is 250,000 km/s.
We can conclude that medium 1 is denser than Medium 2.
In third medium Light speed halts so, the third medium is opaque.
We can say that
Medium 1 can be either water, glass.
Medium 2 will be gas
Medium 3 will be an opaque material.
Answer:
time constant will decrease and steady state current will decrease on increasing the resistance
Explanation:
As we know that the EMF of cell is E which is used to connected across a resistor and an inductor.
So we will have

here we know that

now here we have

so if we increase the value of resistance of the wire then the time constant will decrease
and hence it will take less time to reach near the steady state value
also the steady state current will be smaller in that case
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