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2 years ago

State two factors that affect the type of Shadows formed

Physics

2 answers:

Vadim26 [7]2 years ago

7 0

Answer:

The two factors that affect the type of Shadows formed are stated below ::

The distance between the source of land and the object.
The angel where the ray of light falls on the object.

Dvinal [7]2 years ago

7 0

Answer:

The distance of the source of light from the object.

The angle at which the light rays fall on the object.

The size of the opaque object.

The size of the shadow depends on the distance of the source of light and on the angle at which the light rays fall on the object.

If the source of light is closer to the object, a larger shadow is formed than when the source of light is far from the object.

Explanation:

picture is in the top ️️️⬆️⬆️⬆️⬆️⬆️

It can be observed from the above figure that as the angle of light incident on the object changed the length of the shadow changed.

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3 years ago

Red laser light from a He-Ne laser (λ = 632.8 nm) creates a second-order fringe at 53.2° after passing through the grating. What

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Wavelength of red laser light, $\lambda=632.8\ nm=632.8\times 10^{-9}\ m$

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3 years ago

To push a 26.0 kg crate up a frictionless incline, angled at 25.0° to the horizontal, a worker exerts a force of 209 N parallel

alukav5142 [94]

Answer:

(a) W = +397.1 J

(b) W = -204.6 J

(d) W= + 192.5 J

Explanation:

Work (W) is defined as the product of force (F) by the distance (d)the body travels due to this force. :

W= F*d Formula ( 1)

The forces that perform work on an object must be parallel to its displacement.

The forces perpendicular to the displacement of an object do not perform work on it.

The work is positive (W+) if the force has the same direction of movement of the object.

The work is negative (W-) if the force has the opposite direction of the movement of the object.

Problem development

(a) Work performed by the worker's applied force on the box .

W= 209 N * 1.9 m = +397.1 J

(b) Work performed by the gravitational force on the crate

We calculate the weight component parallel to the displacement of the box:

We define the x-axis in the direction of the inclined plane ,25.0° to the horizontal.

We define the y-axis and in the direction of the plane perpendicular to the inclined plane.

W= m*g=26*9.8= 254.8N : total box weight

Wx= W*sen25.0°= 254.8*sen25.0°= 107.68 N

W = -Wx *d =107.68 N *1.9 m= -204.6 J

(c) Work performed by normal force (N) exerted by the incline on the crate

The force N is perpendicular to the displacement, then:

W=0

(d) Total work done on the crate

W = 397.1 J -204.6 J

W = 192.5 J

4 0

3 years ago

State two factors that affect the type of Shadows formed ​

State two factors that affect the type of Shadows formed