A tennis ball is released from a height of 2.0 m above the floor, and then bounces three times. With each bounce, dissipative fo
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The area under the standard normal curve between z=0.19 and z=2.18 is,
P(0.19<z<2.18)= 0.4101
<h3>How can we calculate the area under the curve?</h3>To calculate the The area under the standard normal curve between z=0.19 and z=2.18, we are using two things,
<u>Step 1</u>: The formula,
P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)
<u>Step 2</u>: The statistical values of the area under the curve we get from the picture.
Now we put the known values from the picture in the above formula, we get,
P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)
Or, P(0.19<z<2.18)= 0.9854-0.5753
Or, P(0.19<z<2.18)= 0.4101
From the above calculation we can easily conclude that,
The area under the standard normal curve between z=0.19 and z=2.18 is,
P(0.19<z<2.18)= 0.4101
Learn more about the standard normal curve:
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