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Alekssandra [29.7K]
3 years ago
10

Red laser light from a He-Ne laser (λ = 632.8 nm) creates a second-order fringe at 53.2° after passing through the grating. What

is the wavelength λ of light that creates a first-order fringe at 22.0°?
Physics
1 answer:
Svetlanka [38]3 years ago
6 0

Explanation:

It is given that,

Wavelength of red laser light, \lambda=632.8\ nm=632.8\times 10^{-9}\ m

The second order fringe is formed at an angle of, \theta=53.2^{\circ}

For diffraction grating,

d\ sin\theta=n\lambda

d=\dfrac{n\lambda}{sin\theta}, n = 2

d=\dfrac{2\times 632.8\times 10^{-9}}{sin(53.2)}

d=1.58\times 10^{-6}\ m

The wavelength λ of light that creates a first-order fringe at 22 is given by :

\lambda=d\ sin\theta

\lambda=1.58\times 10^{-6}\ sin(22)

\lambda=5.91\times 10^{-7}\ m

\lambda=591\ nm

Hence, this is the required solution.

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