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Andrej [43]
1 year ago
11

Fill in the missing term on each line. Simplify any fractions.

Mathematics
1 answer:
e-lub [12.9K]1 year ago
7 0

Answer:

Step-by-step explanation:

4t + 11 = 19

Subtract 11 from both sides

4t = 19 - 11

4t = 8

Divide both sides by 4

t = 8/4

t = 2

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I need help with this.
Sloan [31]

9514 1404 393

Answer:

  61.4

Step-by-step explanation:

The length of two semicircles of diameter 10 is the circumference of a circle of that diameter:

  C = πd = 10π ≈ 31.4

The perimeter includes that length plus the lengths of two straight sides that are 15 units each.

  P = 31.4 + 2×15

  P = 61.4 . . . . units

4 0
3 years ago
A counselor at a community college claims that the mean GPA for students who have transferred to State University is more than 3
Lena [83]

Answer:

t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3  

If we compare the p value and the significance level for example \alpha=1-0.99=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

Step-by-step explanation:

Data given and notation  

\bar X=3.25 represent the sample mean

s=0.3 represent the sample standard deviation

n=36 sample size  

\mu_o =3.1 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is more than 3.1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3.1  

Alternative hypothesis:\mu > 3.1  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3  

P-value  

The first step is calculate the degrees of freedom, on this case:  

df=n-1=36-1=35  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(35)}>3)=0.00247  

Conclusion  

If we compare the p value and the significance level for example \alpha=1-0.99=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

5 0
3 years ago
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harkovskaia [24]
Because if the number was rational then we can tell by looking at the numbers. The rational number should be one number or a repeating decimal or terminating number. plus because if a number was like this 5.7696... that means its irrational because we dont know the end of the number. The rational numbers are terminating numbers or either decimal or repeating numbers because we know the end of those numbers. 
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3 years ago
an art teacher has 28 students in her first period class and 24 in her second period class if almost 30 of the students in these
tatiyna

Answer:

im not sure if this answer is correct but i think its 22

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2 years ago
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48 I think hope this helps
6 0
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