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2 years ago

Nayeli has a points card for a movie theater.

Mathematics

2 answers:

Arisa [49]2 years ago

5 0

Answer: She would have to visit the movie theater 10 times.

Step-by-step explanation:

77julia77 [94]2 years ago

4 0

Step-by-step explanation:

I am not sure what the actual question is.

the general function for the amount of gathered reward points p with v visits to the theater is

p(v) = 14.5×v + 40 (40 starting points, 14.5 points per visit)

to know how many visits are needed for a certain amount of points (185) we need to solve that equation for v :

185 = 14.5×v + 40

145 = 14.5×v

v = 145/14.5 = 10

so, she needs at least 10 visits to gather the desired 185 points for a free ticket.

but that applies only to the first free ticket.

after that the function behavior kind of changes, because we have no more starting points :

so to get 2×185 = 370 points for 2 free tickets she will need

370 = 14.5×v + 40

330 = 14.5×v

v = 330/14.5 = 22.75862069...

we need to round up to the next whole number (because there can be no "part-visits").

so, she will need 23 visits for 2 free tickets (that means 13 more visits for the second free ticket).

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b. There is no evidence that the population mean is above $300.

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d. The director could ask for cheaper similar books.

Step-by-step explanation:

Let X be the random variable that represents the cost of textbooks. We have observed n = 25 values, $\bar{x}$ = 315.4 and s = 43.20. We suppose that X is normally distributed.

We have the following null and alternative hypothesis

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We will use the test statistic

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a. The rejection region is given by RR = {t | t > $t_{0.9}$ } where $t_{0.9} = 1.3178$ is the 90th quantile of the t distribution with 24 df, so, RR = {t | t > 1.3178}. Because the observed value satisty 1.7824 > 1.3178, there is evidence that the population mean is above $300.

b. If s = 75, then the observed value is $t_{0} = \frac{315.4 - 300}{75/\sqrt{25}} = 1.0267$ . The rejection region for a 0.05 level of significance is RR = {t | t > $t_{0.95}$ } where $t_{0.95} = 1.7108$ is the 95th quantile of the t distribution with 24 df, so, RR = {t | t > 1.7108}. Because the observed value does not fall inside the rejection region, there is no evidence that the population mean is above $300.

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d. Because the director of admissions is concerned about the high cost of textbooks, and there is evidence that the population mean of costs is above $300, the director could ask for cheaper similar books.

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Answer:

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Step-by-step explanation:

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