2rabbit 4snake 1owl 3carrot
Answer:
The offsprings of this punnet square will be Dd, Dd, dd and dd in a ratio 1Dd : 1dd
See attached image for punnet square completion
Explanation:
This question involves a cross involving a single gene with alleles D and d where allele D is dominant over allele d i.e. D will mask the phenotypic expression of d in a heterozygous state.
This cross is between a heterozygous parent (Dd) and a homozygous recessive parent (dd). Parent Dd will produce gametes D and d while parent dd will produce gametes d and d.
Using these gametes in a punnet square, four possible offsprings with two distinct genotypes will be produced. The genotypes are: Dd and dd in a ratio 1:1
Hence, the possibility of having a heterozygous dominant offspring is 1/2 while the possibility of having a homozygous recessive offspring is also 1/2.
Each hydrogen bond will form ONE COVALENT bond with the other atoms in the molecule. Hydrogen has only one atom; to form a covalent bond, it has to donate one electron and the other atom that hydrogen is bonding with will donate one electron also, making two. These two electrons will be shared between the two, making the atoms to have two electrons each.
In flowering plants the gametophyte phases are reduced to a few cells dependant for their nutrition on the Sporophyte. The gametophyte comprises the main plant, while the diploid sporophyte is much smaller and is attached to the gametophyte. Both spores and the resulting ganetophyte are haploid, which means they only have one set of chromosomes. The mature gametophyte produces male or female gametes by mitosis. The fusion of male and female gametes produces a diploid zygote which then develops into a new sporophyte.